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3 years ago

11

5/8m + 9 - 3/8m - 15 Please help!!

1 answer:

kondor19780726 [428]3 years ago

8 0

Answer:

-6+m/4

Step-by-step explanation:

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A rectangular parcel of land has an area of 3,000 ft2. A diagonal between opposite corners is measured to be 10 ft longer than o

Kazeer [188]

Answer:

40 ft × 75 ft

Step-by-step explanation:

Let x be the one side ( in feet ) of the rectangular parcel,

So, the diagonal between opposite corners = ( x + 10 ) feet,

Let y be the other side of the rectangle ( adjacent to side x ),

The area of the rectangle,

A = x × y,

According to the question,

A = 3000 square ft,

$\implies xy = 3000\implies y=\frac{3000}{x}$

∵ In a rectangle,

$D^2=a^2+b^2$

Where, a and b are the adjacent side of the rectangle and D is the diagonal,

$(x+10)^2 = x^2 + y^2$

$(x+10)^2 = x^2 + \frac{9000000}{x^2}$

$x^2(x+10)^2 = x^4 + 9000000$

$x^2(x^2+100+20x) = x^4 + 9000000$

$x^4+100x^2 + 20x^3 = x^4 + 9000000$

$20x^3 + 100x^2 - 9000000=0$

$x^3 + 5x^2 - 450000 = 0$

By graphing the equation,

We found that,

The only real zeros of the equation is at x = 75,

Hence, the one side of the rectangle = 75 ft,

And, second side = $\frac{3000}{75}$ = 40 ft

Hence, the dimension of the land is 40 ft × 75 ft

3 0

3 years ago

Read 2 more answers

Triangle ABC is an equilateral triangle with side AB, BC, and AC. If side BC is equal to 10 cm what is the measure of side AC?

nordsb [41]

Answer:

AC = 10 cm

Step-by-step explanation:

We are givne with a triangle ABC is an equilateral triangle with side AB, BC, and AC. We are given that side BC is equal to 10 cm . We are required to find the measurement of side AC.

The basic property of any equilateral triangle is that all the sides are equal. Hence

AB = BC = CA

BC=10 cm

Hence, AB = 10 cm and also AC=10 cm

7 0

3 years ago

Read 2 more answers

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

3 years ago

I need answer how to do number 3

Olegator [25]

You know that you need two already to make one hexagon. So, if you multiply, or add two four times, 2+2+2+2, you would get eight.

3 0

3 years ago

Read 2 more answers

Raj is visiting the united states and needs to convert 2000 rupees to us dollars

Daniel [21]

2,000 rupees to U.S. dollars is $29.50

Hope this helps :)

7 0

3 years ago

Read 2 more answers