<u>Answer</u>
1.333 m/s
<u>Explanation</u>
The momentum before collision and after collision is always conserved.
m₁v₁ = m₂v₂
(0.05×0.6) + (0.03×0) = (0.03 × v) + (0.05 × -0.2)
0.03 + 0 = 0.03v - 0.01
0.03v = 0.03+0.01
0.03v = 0.04
v = 0.04/0.03
= 4/3
=<em> 1.333 m/s</em>
Answer:
A___B___C
AC = AB+ BC
3x +12 = ( 14) + (3-2x)
3x + 12 = – 2x + 17
3x + 2x = 17 - 12
5x = 5
x=5/5
x = 1
AC = 3x + 12 = 3(1) + 12 = 3 + 12= 15
I hope I helped you^_^
Answer: y2/10
Step-by-step explanation:
