The probability that the cat lands on its feet both times it falls out of a tree is 0.85
<h3>How to determine the probability?</h3>
The probability that the cat lands on its feet is given as:
P(Feet) = 0.92
The probability that it lands on its feet twice is calculated using:
P = P(Feet) * P(Feet)
So, we have:
P = 0.92 * 0.92
Evaluate
P = 0.85
Hence, the probability is 0.85
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5,740,000( you have to make the number less than 10
5.740000 ( you put a decimal to make it less )
5.74e6 (you count how many times you skipped over to get at the decimal point , and that's your awnser .
Answer:
Step-by-step explanation:
352 is the answer
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
