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Anvisha [2.4K]
3 years ago
13

Please help me how to get the answer for this one

Mathematics
2 answers:
Snezhnost [94]3 years ago
6 0
The correct answer is each term in patter A is 8 times more than pattern B.
So the answer is D
DanielleElmas [232]3 years ago
3 0

Answer:

i say c sorry if im wrong

Step-by-step explanation:

You might be interested in
A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute
nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

P(k\geq8)=1-P(k

P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\

P(k

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002

5 0
3 years ago
Plzzzzz help i'm in desprate need of help with this
Ainat [17]

Answer:

Obtuse

Step-by-step explanation:

Right = has angle measure of 90°

Acute = has angle measure less than 90°

Equilateral = 2 or more angles whose angle measures are congruent to others

Circle = measures 360°

<u>Obtuse = Angle measure greater than 90° and less than 180°</u>

Hope this helps!

5 0
3 years ago
I need help with this pls
antoniya [11.8K]
I'll explain it simply for you

1st question
Of course you know phythagoras theorm
You even wrote it up there
It states that the sum of the square of the two sides of an equilateral triangle is equal to the square of the hypotenuse
{a}^{2}  +  {b}^{2}   =  {c}^{2}
Where C is the hypotenuse
*NOTE* :
HYPOTENUSE is the greatest side in a triangle!!
And that's where your mistake is!
So you should take the greatest side as C
So in Q3. 7, 24 and 26 are the given numbers
You'll make the smaller two numbers a and b and the greatest number C
Using the Formula you'll solve the left side first which is
{a}^{2}  +  {b}^{2}
Then the right side which is
{c}^{2}

And if both are equal then it is a right triangle otherwise it isn't!
Let
a=7
b=24
c=26


a^2 + b^2
7^2 + 24^2
49 + 576 = 625
GREAT, Now the right side

26^2 = 676
Since they aren't equal it isn't a right angled triangle...

Then let
a=7.5
b=10
c=12.5

7.5^2 + 10^2
= 56.25 + 100
= 156.25



12.5^2 = 156.25

They are EQUAL
Therefore it is a right triangle too

Hopefully I helped
7 0
3 years ago
Help will be greatly appreciated!!! Write the system of equations for these two lines.
Darya [45]

Answer:

See answer below:

Step-by-step explanation:

Blue: y=2x+1

Red: y=3x-2

5 0
2 years ago
Wen Naey started mkkdle sehool, she was 60 inches tall, When she started high school, she was 65 inches tal. V/h
Svetlanka [38]
The first one is the answer
7 0
2 years ago
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