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Anvisha [2.4K]
3 years ago
13

Please help me how to get the answer for this one

Mathematics
2 answers:
Snezhnost [94]3 years ago
6 0
The correct answer is each term in patter A is 8 times more than pattern B.
So the answer is D
DanielleElmas [232]3 years ago
3 0

Answer:

i say c sorry if im wrong

Step-by-step explanation:

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The table below shows the cube roots of different numbers:
Mila [183]

part A)

\bf \begin{array}{|c|cccccc|ll} \cline{1-7} x&8&27&64&125&&x\\ \cline{1-7} y&\stackrel{\sqrt[3]{8}}{2}&\stackrel{\sqrt[3]{27}}{3}&\stackrel{\sqrt[3]{64}}{4}&\stackrel{\sqrt[3]{125}}{5}&&\sqrt[3]{x} \\ \cline{1-7} \end{array}~\hspace{10em}y = \sqrt[3]{x}

part B)

f(x) = 10 + 20x

so if you rent the bike for a few hours that is

1 hr.............................10 + 20(1)

2 hrs..........................10 + 20(2)

3 hrs..........................10 + 20(3)

so the cost is really some fixed 10 + 20 bucks per hour, usually the 10 bucks is for some paperwork fee, so you go to the bike shop, and they'd say, ok is 10 bucks to set up a membership and 20 bucks per hour for using it, thereabouts.

f(100) = 10 + 20(100) => f(100) = 2010.

f(100), the cost of renting the bike for 100 hours.

4 0
3 years ago
Answer please I will give brainiest to the one who answers first.
Lerok [7]

Answer:

  • $1,094,748.09
  • $8600.28
  • 11 years, 10 months

Step-by-step explanation:

a) The compound interest formula can be used:

  A = P(1 +r/n)^(nt)

where P is the principal invested at annual rate r compounded n times per year for t years.

  A = $750,000(1 +.038/4)^(4·10) ≈ $1,094,748.09

Tamsyn's account will have a balance of $1,094,748.09 when she retires.

__

b1) The amortization formula is good for this.

  A = P(r/n)/(1 -(1 +r/n)^(-nt))

where P is the amount earning interest at annual rate r compounded n times per year for t years.

  A = $1,094,748.09(0.049/12)/(1 - (1 +0.049/12)^(-12·15)) ≈ $8600.28

Tamsyn can withdraw $8600.28 per month for 15 years.

__

b2) The account balance after n months will be ...

  B = P(1 +r/12)^n -A((1+r/12)^n -1)/(r/12)

Filling in the known values and solving for n, we have ...

  300,000 = 1,094,748.09(1.1.00408333^n) -8600.28(1.00408333^n -1)/.000408333

  300,000 = 1,094,748.09(1.1.00408333^n) -2,106,191.02(1.00408333^n -1)

  -1,806,191.02 = -1,011,442.93(1.00408333^n)

  1.785757 = 1.00408333^n

  n = log(1.785757)/log(1.00408333) = 142.3

After about 11 years 10 months, the account balance will be $300,000.

4 0
3 years ago
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

4 0
3 years ago
Using the following image, find GH given HI = 1 and GI =<br> = 9.
shepuryov [24]

Answer:

8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Need help on number 2 plz I appreciate it thank you so much
vladimir1956 [14]

Answer:

\angle PQR, \angle SQR, and \angle PQS

Or

angle PQR, angle SQR and angle PQS

Step-by-step explanation:

The three different angles in the diagram are angle PQR, angle SQR and angle PQS.

Another way of writing this is using an angle sign before the alphabets follows. Thus:

\angle PQR, \angle SQR, and \angle PQS

6 0
3 years ago
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