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2 years ago

Christina has 40 coins in her collection. she has 21 fewer coins in her collection than shaya has in hers.

Mathematics

1 answer:

KATRIN_1 [288]2 years ago

6 0

A. and b. 40+21=61 coins has shaya
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Drag numbers to the table so it shows a proportional relationship between x and y.

Yakvenalex [24]

Answer:

the second box for y is 9

the third box for x is 2.5

im not sure about the third box for y

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2 years ago

There are 20 children in the cast of a class play, and 8 of the children are boys. of the boys, 4 have a speaking part in the pl

kotykmax [81]

<span>it all looks confusing when we try to juggle with all those numbers in the head. The problem can be solved systematically by constructing a contingency table.
</span>role/gender B G total
speaking...... 4 4 8
<span> silent............ 4 8 12
total............. 8 12 20
</span>Probability of a child having a speaking part is therefore
(4+4)/20=8/20=2/5
a. 2/5

5 0

3 years ago

Read 2 more answers

Geometry help needed! Thanks.

VMariaS [17]

EN = NE

Answer

D. last one

4 0

2 years ago

Question Help

Lady bird [3.3K]

Answer:

19 1-point shots and 32 2-point shots

Step-by-step explanation:

Let x be the amount of 1-point shots they made and y be the amount of 2-point shots they made then...

x+y=51

x+2y=83

We can solve this equation using elimination. In this case, we can eliminate x be subtracting the two equations.

-y=-32

Divide both sides by -1

y=32

Plug this back into the equation to solve for x

x+32=51

Subtract 32 from both sides

x=19

They scored 19 1-point shots and 32 2-point shots.

8 0

2 years ago

The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

4 0

2 years ago