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julia-pushkina [17]
3 years ago
7

Christina has 40 coins in her collection. she has 21 fewer coins in her collection than shaya has in hers.

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0
A. and b. 40+21=61 coins has shaya
................................................
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Consider the quadratic function f(x) = –2x2 + 5x – 4.
liq [111]

Answer:

2.

Step-by-step explanation:

That is the coefficient of x^2 = 2.

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3 years ago
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Evaluate z + z + z for x = 2, y = -3, z = -4.
Dvinal [7]
Greetings!

"<span>Evaluate z + z + z for x = 2, y = -3, z = -4."...

Input the information given:
(-4)+(-4)+(-4)
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4 years ago
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What is the area of the composite figure 262 264 266 268
sineoko [7]

Answer:

264cm2

Step-by-step explanation:

the length of line in green = 5 cm

the length of line in yellow = 3 cm

the length of line in red = 6 cm

the length of line in white = 16 cm

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4 years ago
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If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
harina [27]

Answer:

10

Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

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2+2+6=10

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8 0
4 years ago
Use the quadrant system to find the area of the polygon
AfilCa [17]

Answer:

The area of the polygon is 64 units²

Step-by-step explanation:

* Lets explain how to solve the problem

- The polygon has 5 sides and 5 vertices

- To find its area by easy way split it into two trapezoid by a horizontal

  line y = 1

- The vertices of trapezoid (1) are (-5 , 1) , (4 , 1) , (-5 , 5) , (0 , 5)

- The vertices of one of the parallel bases are (-5 , 1) , (4 , 1)

- The length of this base = 4 - (-5) = 4 + 5 = 9 units

- The vertices of the other parallel bases are (-5 , 5) , (0 , 5)

- The length of this base = 0 - (-5) = 0 + 5 = 5 units

- The length of its height = 5 - 1 = 4 units

- The area of the trapezoid = 1/2 (b1 + b2) × h

∴ Area of trapezoid 1 = 1/2 (9 + 5) × 4 = 28 units²

- The vertices of trapezoid (2) are (4 , 1) , (-5 , 1) , (-5 , -5) , (-2 , -5)

- The vertices of one of the parallel bases are (4 , 1) , (-5 , 1)

- The length of this base = 4 - (-5) = 4 + 5 = 9 units

- The vertices of the other parallel bases are (-5 , -5) , (-2 , -5)

- The length of this base = (-2) - (-5) = -2 + 5 = 3 units

- The length of its height = 1 - (-5) = 1 + 5 = 6 units

∴ Area of trapezoid 1 = 1/2 (9 + 3) × 6 = 36 units²

∵ Area of the polygon = Area trapezoid (1) + Area trapezoid (2)

∵ Area trapezoid (1) = 28 units²

∵ Area trapezoid (2) = 36 units²

∴ Area of polygon = 28 + 36 = 64 units²

∴ The area of the polygon is 64 units²

3 0
4 years ago
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