∠ABX is an inscribed angle.
The measure of an inscribed angle is half the measure of the intercepted arc ⇒
arc AX = 2*∠ABX = 2 * 64 = 128°
The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the <span>intercepted arcs </span>⇒
∠ACB = (arc AB - arc AX)/2 = (152 - 128)/2 = 24/2 = 12°
Answer:
34
Step-by-step explanation:
5x+2(3+x)
The first step is to distribute the 2
5x+2*3 + 2x
5x+6+2x
Combine like terms
7x+6
Now substitute x=4
7*4+6
28+6
34