Answer:
1st box: Asso. prop= m+(4+x)
2nd box: Comm. Prop= m+4=4+m
3rd box: iden. prop= m+0=m
4th box: Zero prop: m x 0=0
Answer:
<em>Answer: Quadrant 4</em>
Step-by-step explanation:
<u>Graph of Functions
</u>
Let's analyze the function

To better understand the following analysis, we'll factor y

For y to have points in the first quadrant, at least one positive value of x must produce one positive value of y. It's evident that any x greater than 0 will do. For example, x=1 will make y to be positive in the numerator and in the denominator, so it's positive
For y to have points in the second quadrant, at least one negative value of x must produce one positive value of y. We need two of the factors that are negative. It can be seen that x=-2 will make y as positive, going through the second quadrant.
For the third quadrant, we have to find at least one value of x who produces a negative value of y. We only need to pick a value of x that makes one or all the factors be negative. For example, x=-4 produces a negative value of y, so it goes through the third quadrant
Finally, the fourth quadrant is never reached by any branch because no positive value of x can produce a negative value of y.
Answer: Quadrant 4
Answer:
2,500) (60,000
brain pls
Step-by-step explanation:
Answer:
6+3-8-7 = 8
1+4+10-8 = 7
3-3+9+1 = 10
10-2+10-8 = 10
2+0+1+2+3 = 8
10-1-2-3+4 = 8
Step-by-step explanation:
i don't know if these are supposed to be easy or not lol but thanks for the points :p