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iren [92.7K]
3 years ago
14

In the rectangle ABCD the angle OAV is 48degrees smaller than the angle AOB .Find the angles of the triangle AOB

Mathematics
1 answer:
mart [117]3 years ago
3 0
Im giving you instrutions to get the answer its simple:D
The figure above shows a circular sector OAB<span> , subtending an </span>angle<span> of θ radians ... The points A and B lie on the circle so that the </span>angle AOB<span> is 1.8 radians. .... c) </span>Calculate<span> the smallest </span>angle<span> of the </span>triangle<span>ABC , giving the answer in </span>degrees<span>, .... Given that the length of the arc AB is </span>48<span> cm , </span>find<span> the area of the shaded region</span><span>.
</span>
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padilas [110]
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Since 16+16+16+16 is the same as 4*16 I'l just make it 3*16 (because you minus 16 from it)

3*16 ? 4[24-2(4+8)]
48 ? 4[24-2(4+8)]
48 ? 4[24-2*12]
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49>0

So it is a >

Hope this helps :)
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4 years ago
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Step-by-step explanation:

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