A small child makes 3 piles of blocks in a room. Each pile has 4 blocks. In another room, he makes 6 more piles of blocks. These
piles also have 4 blocks each. To count the total number of blocks, his sister counts that there are 3 times 4, or 12 blocks, in one room and 6 times 4, or 24 blocks, in the other room for a total of 36 blocks. Using the distributive property, what is another way she could have counted the blocks?
·She could have added the number of piles before multiplying by 4.
·She could have found the number of blocks in 4 piles and added it to the number of blocks in 5 piles.
·She could have switched the order in which she added the 12 and 24.
·She could have counted each block separately.
<h3>Hello there i hope you are having good day :) Question : Solve the problem by writing an inequality. = A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T-shirt to make the T-shirts. Write and solve an equation to find how many T-shirts the club needs to make and sell in order to profit at least $100. Show your work? = So firstly the each of the shirt cost $12 and the money made for the shirt equals 12$ so the cost per the shirt would be 20 + 8x that lead to needing at least 100$ amount made - cost = profit would equal to 12x - (20-8x) ≥ 100 then you would do 12x-20-8x = 100 then you would also do 4x-20 = 100 then you add 20 and add 20 again that would equal 4x/4x = 120/4 that would finally lead you to the answer that would be x = 30 ---> x ≥ 30</h3><h3>Hopefully this help you.</h3>
