A function has f''(x) = 10 and has f'(4) = 0 and f(2) = 4. Find f(x)
1 answer:
Answer:
f(x) = 5x^2 - 40x + 64
Step-by-step explanation:
f''(x) = 10
f'(x) = 10x + a
f'(4) = 0 = 10*4 + a
a = -40
So f'(x) = 10x - 40
f(x) = 5x^2 - 40x + b
f(2) = 4 = 5*2^2 - 40*2 + b
4 = 20 - 80 + b
b = 64
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