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enot [183]
3 years ago
11

30/49(-63/40) please solve

Mathematics
2 answers:
Allisa [31]3 years ago
7 0

Answer:

-27/28

hope this helps :D have a good day

kati45 [8]3 years ago
4 0

Answer:

Your answer is -27/28

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Solve the equation below
Agata [3.3K]
Set up the equation:

4(8.75x-2)=97
35x-8 =97
35x =97+8
35x =105
x. =3

The value of x is 3.
7 0
2 years ago
Find the area of square if the length of its diagonal is 18 cm​
NikAS [45]

Answer:

324

Step-by-step explanation:

5 0
3 years ago
If you take -3/10 of a number and add 1, you get 10. Write an equation to represent the situation. What is the original number?
Basile [38]
Equation - x = -3/10 + (10-1)

The original number is 9.3 because
x = -3/10 + (10-1)
x = -3/10 + 9
x = 9.3

4 0
3 years ago
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
1 year ago
Which two points have a undefined slope
allochka39001 [22]

Answer:

C.(-3, -3) and (-3,3)

Step-by-step explanation:

When we have a vertical line the slope is undefined.

That means the x values stay the same

C.(-3, -3) and (-3,3)

This has the same x values

m = (y2-y1)/(x2-x1)

   =( 3- -3)/(-3 - -3)

   (3+3)/(-3+3)

   6/0

  undefined

7 0
3 years ago
Read 2 more answers
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