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ss7ja [257]
2 years ago
14

i jave a 5 in my ones place. the digit in my tens place os 3 plus the digit in my ones place. the digit in my hundreds place is

2 less than the digit in my ones place. what number am i?​
Mathematics
1 answer:
KatRina [158]2 years ago
4 0

Answer:

The number is 385.

Step-by-step explanation:

The 5 is in the ones place so you put that at the end. The digit in the tens place is 3 plus the digit in the ones place which is 5 so 3 + 5 = 8 so the 8 is in the tens place. The digit in the hundreds place is 2 less than the digit in the ones place which is 5 so 5 - 2 = 3 so the 3 is in the hundreds place

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Tpy6a [65]

Answer:

The answer would be greater since its being multiply the answer will always be greater than what you're multiplying.

Step-by-step explanation:

The product WILL be greater than the other two factors. When multiplying by a fraction the product is GREATER than the lesser factor.

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3 years ago
6f+f(f+2)+3 f*to the 2nd power-4f​
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Answer:

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Frank wants to buy three items costing $111.32, $28.75, and $73.21. If he earns $8.75 an hour, how many hours must Frank work be
Sedaia [141]

The three items cost altogether is : 111.32 + 28.75 + 73.21 = 213.28

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4 0
2 years ago
6-10 divide, another onee thank you!!​
eduard

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

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The segment AB in the following represents a diameter.
Andre45 [30]

Answer:

It's true

Step-by-step explanation:

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