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4vir4ik [10]
3 years ago
11

Rachel types 162 words in 3 minutes how many words did rachel type pure minute

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0

Answer:

54

Step-by-step explanation:

162/3=54

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Points A, B, C and D have coordinates A(5, 7), B(7, 1), C(17, m) and D(−1, 3). If line
STatiana [176]

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3

Step-by-step explanation:

I used  a graph

6 0
3 years ago
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Help me pleaseee.....
Lana71 [14]

Answer:

titutex=cos\alp,\alp∈[0:;π]

\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+

1−x

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∣=

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(2x

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−1)\Leftright∣cos\alp+sin\alp∣=

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\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N

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cos(\alp−

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cos(2\alp)\Right\alp∈[0;

4

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3π

;π]

1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;

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π

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\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−

4

π

)=cos(2\alp)…

2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[

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\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−

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π

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6 0
4 years ago
Solve the equation and check your solution. (If an answer does not exist, enter DNE. If all real numbers are solutions, enter RE
r-ruslan [8.4K]
5x-4=4x+8
-4x. -4x
X-4=8
+4. +4
X=12
5(12)-4=4(12)+8
60-4=48+8
56=56
5 0
3 years ago
What is the GCF for 7x2 + 21?
laiz [17]

Answer:

35

Step-by-step explanation:

<u>7x2</u>+21

<u>14+21</u>

35

*The underlined problems is what you do first*

4 0
3 years ago
What point in the feasible region maximizes the objective function, 3x + y ≤ 12, x+y ≤5, x ≥0,y ≥0
forsale [732]

Step-by-step explanation:

We have to find the point in the feasible region which maximizes the objective function. To find that point first we need to graph the given inequalities to find the feasible region.

Steps to graph 3x + y ≤ 12:

First we graph 3x + y = 12 then shade the graph for ≤.

plug any value of x say x=0 and x=2 into 3x + y = 12 to find points.

plug x=0

3x + y = 12

3(0) + y = 12

0 + y = 12

y = 12

Hence first point is (0,12)

Similarly plugging x=2 will give y=6

Hence second point is (2,6)

Now graph both points and joint them by a straight line.

test for shading.

plug any test point which is not on the graph of line like (0,0) into original inequality 3x + y ≤ 12:

3(0) + (0) ≤ 12

0 + 0 ≤ 12

0 ≤ 12

Which is true so shading will be in the direction of test point (0,0)


We can repeat same procedure to graph other inequalities.

From graph we see that ABCD is feasible region whose corner points will result into maximum or  minimu for objective function.

Since objective function is not given in the question so i will explain the process.

To find the maximum value of objective function we plug each corner point of feasible region into objective function. Whichever point gives maximum value will be the answer

7 0
3 years ago
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