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melisa1 [442]
3 years ago
12

Which are malicious codes? JavaScript Key loggers Scrum Spyware Worms

Computers and Technology
1 answer:
max2010maxim [7]3 years ago
5 0

Keyloggers, spyware, and worms.

You might be interested in
Help help help help help help
Shkiper50 [21]

Answer:

maybe overexposure???

Explanation:

6 0
2 years ago
Look at the logic program below. Set a breakpoint after each commented instruction. You can also single step through the program
Goshia [24]

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

<h3>Writing the code and understanding the programming logic:</h3>

<em>.data</em>

<em>sourceword:</em>

<em>.word 0xAB</em>

<em>wordmask:</em>

<em>.word 0xCF</em>

<em>operand:</em>

<em>.long 0xAA</em>

<em>.text</em>

<em>.globl _start</em>

<em>_start:</em>

<em>movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)</em>

<em>movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)</em>

<em>xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)</em>

<em />

<em>andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)</em>

<em>orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)</em>

<em>xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)</em>

<em />

<em>movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)</em>

<em>movl %eax, %ebx # ebx=0x000000AA.( copy the value of eax to ebx.)</em>

<em>movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)</em>

<em />

<em>shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em># =>00000000000000000000010101010000=0x00000550.</em>

<em />

<em>rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em>3 =>10100000000000000000000000001010= 0xA000000A.</em>

<em />

<em>sarl %ecx # here the count value to shift the bits not mentioned.</em>

<em />

<em># It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.</em>

See more about logic program at brainly.com/question/14970713

#SPJ1

5 0
2 years ago
How to hack my neighboor wireless?​
guapka [62]

Answer:

 

How to Hack your Neighbor’s WiFi Password Using Tools

BY NEVIL PATELLEAVE A COMMENT

Getting a WiFi connection is a major concern once you are addicted to the web and mostly in the online world. When we hear the term hack, it strikes in our mind that it is the job of a high-end technology guy or a hacker. But to “hack WiFi password”, you don’t need to be a skilled technologist because even a non-technical guy can do it with some tricks and methods.

Most people have asked me the procedure to crack WiFi passwords, so today I am here with the solution and tricks for internet hack free WiFi from the major providers like AT&T, Comcast, and Xfinity.

 

wifi-password-hack

P.S. The WiFi password hacker tools are meant for fun/general purpose only and do not contain any functionality to attempt criminal acts. Therefore, you should be very cautious while operating them.

Wifi Hacker tools

(1) WiFi Hacker

WiFi Hacker is a simple and informal tool that makes hacking WiFi easy and safe without having required any technical knowledge. This software can crack WiFi passwords with some clicks and hack unlimited WiFi networks. WiFi Hacker gives you access to multiple offices or school wifi networks, including Comcast, AT&T, etc. which are equipped with tighter security. You can hack any locked password within minutes and anonymously because WiFi Hacker conceals your identity and personal information.

Explanation:

muwhahaha

7 0
2 years ago
Given that it takes 0.08 ms to travel from one track to the next of a hard drive; that the arm is originally positioned at Track
daser333 [38]

Answer:

Time taken to travel from one track to the next = 0.08ms

Initial track= 15     0

4      (15-4)*(0.08)= 0.88

40     (40-4)*(0.08)= 2.88

35      (40-35)*(0.08)= 0.4

11       (35-11)*(0.08)= 1.92

14       (14-11)*(0.08)= 0.24

7         (14-7)*(0.08)= 0.56

----------------------------------------------

Total seek time=0.88+2.88+0.4+1.92+0.24+0.56=6.88ms

Explanation:

We caculate the seek time for each request, and then add them together to find the total seek time. The final track number for the current request becomes the current track of next request, and this process is repeated till the last request is processed.

4 0
3 years ago
QUESTION 5
lesya692 [45]
I’m pretty sure D but it should be like $B2
8 0
2 years ago
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