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ch4aika [34]
3 years ago
6

How to hack my neighboor wireless?​

Computers and Technology
1 answer:
guapka [62]3 years ago
7 0

Answer:

 

How to Hack your Neighbor’s WiFi Password Using Tools

BY NEVIL PATELLEAVE A COMMENT

Getting a WiFi connection is a major concern once you are addicted to the web and mostly in the online world. When we hear the term hack, it strikes in our mind that it is the job of a high-end technology guy or a hacker. But to “hack WiFi password”, you don’t need to be a skilled technologist because even a non-technical guy can do it with some tricks and methods.

Most people have asked me the procedure to crack WiFi passwords, so today I am here with the solution and tricks for internet hack free WiFi from the major providers like AT&T, Comcast, and Xfinity.

 

wifi-password-hack

P.S. The WiFi password hacker tools are meant for fun/general purpose only and do not contain any functionality to attempt criminal acts. Therefore, you should be very cautious while operating them.

Wifi Hacker tools

(1) WiFi Hacker

WiFi Hacker is a simple and informal tool that makes hacking WiFi easy and safe without having required any technical knowledge. This software can crack WiFi passwords with some clicks and hack unlimited WiFi networks. WiFi Hacker gives you access to multiple offices or school wifi networks, including Comcast, AT&T, etc. which are equipped with tighter security. You can hack any locked password within minutes and anonymously because WiFi Hacker conceals your identity and personal information.

Explanation:

muwhahaha

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Sergeu [11.5K]

Answer:

import java.util.Scanner;

public class num3 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter Favorite color");

       String word1 = in.next();

       System.out.println("Enter Pet's name");

       String word2 = in.next();

       System.out.println("Enter a number");

       int num = in.nextInt();

       //Point One

       System.out.println("You entered: "+word1+" "+word2+

               " "+num);

       //Point Two

       String passwordOne = word1+"_"+word2;

       String passwordTwo = num+word1+num;

       System.out.println("First password: "+passwordOne);

       System.out.println("Second password: "+passwordTwo);

       //Point Three

       int len_passwrdOne = passwordOne.length();

       int len_passwrdTwo = passwordTwo.length();

       System.out.println("Number of characters in "+passwordOne+" :" +

               " "+len_passwrdOne);

       System.out.println("Number of characters in "+passwordTwo+" :" +

               " "+len_passwrdTwo);

   }

}

Explanation:

  • This question is solved using java programming language
  • The scanner class is used to receive the three variables (Two string and one integer)
  • Once the values have been received and stored in the respective variables (word1, word2 and num), Use different string concatenation to get the desired output as required by the question.
  • String concatenation in Java is acheived with the plus (+) operator.
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A radio and communications security repairer is responsible for both radio and satellite communication systems.
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Find the inverse function of f(x)= 1+squareroot of 1+2x
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Answer:

Therefore the inverse function of  f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

Explanation:

We need to find the inverse of function f(x)=1+\sqrt{1+2x}

Function Inverse definition :

\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}

y=1+\sqrt{1+2x}\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y

x=1+\sqrt{1+2y}

\mathrm{Solve}\:x=1+\sqrt{1+2y}\:\mathrm{for}\:y

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+\sqrt{1+2y}-1=x-1

Simplify

\sqrt{1+2y}=x-1

\mathrm{Square\:both\:sides}

\left(\sqrt{1+2y}\right)^2=\left(x-1\right)^2

\mathrm{Expand\:}\left(\sqrt{1+2y}\right)^2:\quad 1+2y

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1+2y=x^2-2x+1

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+2y-1=x^2-2x+1-1

\mathrm{Simplify}

2y=x^2-2x

\mathrm{Divide\:both\:sides\:by\:}2

\frac{2y}{2}=\frac{x^2}{2}-\frac{2x}{2}

\mathrm{Simplify}

y=\frac{x^2-2x}{2}

Therefore the inverse function of f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

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