The graph of y = -2x + 3 is a straight line
Its slope is - 2
Its y-intercept is + 3
To draw the line you can use these two points (0,3) and (3/2 , 0)
This line does ont pass through the third quadrant. It comes downward from the second quadrant, touches the y-axis at y =3, continues on the rirst quadrant, touches the x-axis at x = 3/2, and contiues into the fourth quadrant.
Graph of its inverse
Exchange y and x in the given function and solve for the new y
x = - 2y + 3 => y = - x/2 + 3/2
It is also a straight line;
Its slope is -1/2
Its y-intercept is 3/2
It is also in the second, first and fourth quadrant
Use these two points to draw the line (0,3/2) and (3,0).
You do not need to know to draw this, but the inverse of a function is its reflection through the line y =x.
I’m pretty sure it’s the first option, if not I am so sorry.
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