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V125BC [204]
3 years ago
7

There are two sets of traffic lights outside Eric's house. One day, he times how often they change. Set A turns green every 60 s

econds. Set B turns green every 70 seconds. At midday precisely they both turn green together.
At what time will they both turn green together again?


Pls I need help, I'm stuck​
Mathematics
2 answers:
Art [367]3 years ago
4 0

Answer:

12:07 or 7 minutes into midday

Step-by-step explanation:

You have to find the Least/lowest common multiple (LCM) of 60 and 70 which  is 420.

So you divide 420 by 60 (60 second in a minute) which gives you the answer

7. So if you add 7 minutes into midday/add 7 minutes into 12:00,

it gives you the answer

<u><em>12:07 or 7 minutes into midday</em></u>

Otrada [13]3 years ago
3 0

Answer:

12:07pm

Step-by-step explanation:

first common multiple of 60 and 70 is 420

420 s = 7 mins

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The sum of three numbers in <br> g.p. is 21 and the sum of their squares is 189. find the numbers.
sashaice [31]
Let the three gp be a, ar and ar^2
a + ar + ar^2 = 21 => a(1 + r + r^2) = 21 . . . (1)
a^2 + a^2r^2 + a^2r^4 = 189 => a^2(1 + r^2 + r^4) = 189 . . . (2)
squaring (1) gives
a^2(1 + r + r^2)^2 = 441 . . . (3)
(3) ÷ (2) => (1 + r + r^2)^2 / (1 + r^2 + r^4) = 441/189 = 7/3
3(1 + r + r^2)^2 = 7(1 + r^2 + r^4)
3(r^4 + 2r^3 + 3r^2 + 2r + 1) = 7(1 + r^2 + r^4)
3r^4 + 6r^3 + 9r^2 + 6r + 3 = 7 + 7r^2 + 7r^4
4r^4 - 6r^3 - 2r^2 - 6r + 4 = 0
r = 1/2 or r = 2
From (1), a = 21/(1 + r + r^2)
When r = 2:
a = 21/(1 + 2 + 4) = 21/7 = 3
Therefore, the numbers are 3, 6 and 12.
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3 years ago
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CORRECT ANSWER WITH A GOOD EXPLANATION WILL GET BRAINLIEST + 15 POINTS ASAP
arsen [322]

Answer:

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Step-by-step explanation:

So.

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