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3 years ago

What is the median of 100, 75, 40, 90, 80, 100, 92, 88, 80, 84, 81? I got 82 but it wasn’t right.

2 answers:

6 0

The median is what number is the middle so list the number in order and remove 1 from each end until you get to the last number

So you get 84

Answer: 84

Work 40,75,80,80,81, 84 ,88,90,92,100,100

Nataly_w [17]3 years ago

3 0

To start you have to order the numbers from least to greatest, getting 40, 75, 80, 80, 81, 84, 88, 90, 92, 100, 100. Then you would take out the end number on each side, getting 75, 80, 80, 81, 84, 88, 90, 92, 100. You continue taking numbers off the end until you get to the middle number, or the middle two numbers if there is an even amount of numbers, which would give you the median 84. If you had an even amount of numbers and got down to two numbers, you would add them together and divide them by two.

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Stephan con run 3 miles in 15.75 minutes. Keisha con run 5 miles in 22.6 minutes. Who can run faster?

Marina CMI [18]

Answer: Keisha can run faster than Stephan.

Step-by-step explanation:

Let's figure out how long it takes for them to run a mile.

$\frac{15.75}{3} =5.25\\\frac{3}{3} = 1$

It would take Stephan 5.25 minutes to run a mile

$\frac{22.6}{5} =4.52\\\\\frac{5}{5} =1$

It would take Keisha 4.52 minutes to run a mile

Since Keisha takes less time to run a mile she is faster.

3 0

3 years ago

Read 2 more answers

Factor the trigonometric equation.<br> cos2x-cosx

prisoha [69]

Cos(2x) = cos^2(x) - sin^2(x) - cos(x)

but sin^2(x) = 1 - cos^2(x)

cos(2x) - cos(x) = cos^2(x) - (1 - cos^2(x) ) - cos(x)

cos(2x) - cos(x) = cos^2(x) - 1 + cos^2(x) - cos(x)

cos(2x) - cos(x) = 2cos^2(x) - 1 - cos(x)

cos(2x) - cos(x) = (2cos(x) + 1)(cos(x) - 1)

I think this is what you have asked for.

4 0

3 years ago

Hey hey hey. help pls

Firdavs [7]

Answer:

Emma spend 8 hours in homework in a week and Jared spends 16 hours in homework in 2 weeks.

Step-by-step explanation:

Two quantities P and Q are said to be in PROPORTION if and only if for all values of P and q, we get:

$\frac{P}{Q} = k$

Here, k : PROPORTIONALITY CONSTANT

Case: 1

5 hour piano practice in 1 week.

So, the piano practice in 2 weeks( 1 x 2) = 2 x 5 = 10 hours

But here, it is given to be 12 hours in 2 weeks.

Hence, NOT PROPORTIONAL.

Case 2:

70 words in 60 seconds.

So, the words typed in 210 seconds ( 60 x 3.5) = 70 x 3.5 = 240 words

But here, it is given to be 280 words in 210 seconds.

Hence, NOT PROPORTIONAL.

Case: 3

8 hour homework in 1 week.

So, the homework done in 2 weeks( 1 x 2) = 2 x 8 = 16 hours

It is given to be 16 hours in 2 weeks.

Hence, PROPORTIONAL.

Case: 4

15 miles in 78 minutes.

So, the distance covered in 102 minutes (78 x 1.3) = 15 x 1.3 = 19.6 miles

But here, it is given to be 17 miles in 102 minutes.

Hence, NOT PROPORTIONAL.

Case: 5

18 miles in 45 minutes.

So, the distance covered in 55 minutes (45 x 1.2) = 18 x 1.2 = 21.6 miles

But here, it is given to be 22 miles in 55 minutes.

Hence, NOT PROPORTIONAL.

Hence, the only proportional case is Emma spend 8 hours in homework in a week and Jared spends 16 hours in homework in 2 weeks.

6 0

3 years ago

Read 2 more answers

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lawyer [7]

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3 0

2 years ago

What is Permutations and Combinations?

marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

$\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }$

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

$\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}$

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

$\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }$

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

$\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}$

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0

2 years ago