Answer:
The average rate of change between these times is 68 miles per hour
Step-by-step explanation:
Here, we are to determine the average rate of change between hour 2 and hour 7
The distance traveled at hour 2 is 140 miles
The distance traveled at hour 7 is 480 miles
So we can say we have two points and we want to know the rate of change between these points
Mathematically, we can represent the rate of change as Δ
Thus, between the two different times, we have;
Δ = (D7-D2)/(T7-T2)
where (T7,D7) = (7,480) and (T2,D2) = (2,140) represents the time and distance at hour 2 and hour 7 respectively
Now inputing the values into the equation, we have;
Δ = (480-140)/(7-2) = 340/5 = 68 miles/hour
Quick answer I don't think this has an answer.
If you take the cos-1(2 sqrt(2)) your calculator should have a fit. Let's check that out. Mine certainly does. So there is something wrong with the question. If there is something to add in please do it and I will it least put an answer in the comments. As it stands, nothing will work.
If you put your calculator in radians, you will get an answer but it will not be anything resembling the choices you've listed.
If you meant sqrt(2) / 2 that would give 45o. Put it in your calculator like this 2 ^ 0.5 divided by 2 = 0.707
Cos - 1 (0.707) = 45
Answer:
C -(-6.53)+4.11-(-7.92)−(−6.53 )+4.11−(−7.92)minus, left parenthesis, minus, 6, point, ...
Answer: Choice B and Choise C.Step-by-step explanation: Equivalent expressions are those expressions that have the same value but they look different.
The effect on the photos perimeter and area would be that the resulting photo would be larger than intended.
The answer is C (289pi/6 mi2)
