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Hoochie [10]
3 years ago
8

Which statement best describes the effect of color on energy absorption and reflection? 1. Light colors reflect more and absorb

less than dark colors. 2.Light colors reflect less and absorb more than dark colors. 3.Light colors absorb and reflect more than dark colors.
4.Light colors absorb and reflect less than dark colors.
Chemistry
2 answers:
fredd [130]3 years ago
8 0
The statement which best described the effect of color on energy absorption and reflection is this: LIGHT COLORS REFLECT MORE AND ABSORB LESS THAN DARK COLORS. Black color absorbs all incident radiations while white color reflects all incident radiations; all other colors fall in the midst of these two colors.
goldfiish [28.3K]3 years ago
6 0

(Rough surfaces absorb more energy than smooth surfaces.)

hope this helps!!!!!:)

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Calculate the standard enthalpy change of formation of CHA given that the standard enthalpies change of combustion of methane, g
Nostrana [21]

Answer : The standard enthalpy of formation of methane is, -74.8 kJ/mole

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of CH_4 will be,

C(s)+2H_2(g)\rightarrow CH_4(g)    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l)     \Delta H_1=-890kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.4kJ/mole

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-285.7kJ/mole

Now we will reverse the reaction 1, multiply reaction 3 by 2 then adding all the equations, we get :

(1) CO_2(g)+2H_2O(l)\rightarrow CH_4(g)+2O_2(g)     \Delta H_1=890kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.4kJ/mole

(3) 2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=2\times (-285.7kJ)=-571.4kJ/mole

The expression for enthalpy of formation of CH_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+890kJ/mole)+(-393.4kJ/mole)+(-571.4kJ/mole)

\Delta H=-74.8kJ/mole

Therefore, the standard enthalpy of formation of methane is, -74.8 kJ/mole

3 0
3 years ago
Gas expands as it heats up. We call this phenomena...
ra1l [238]

I believe the answer is thermal expansion.

7 0
3 years ago
Read 2 more answers
What is the percent abundance of Pt-198, if the average atomic mass of platinum is 195.16 and platinum has four naturally occurr
nlexa [21]

Answer:

Explanation:

8%

5 0
3 years ago
A potential energy diagram is shown. A graph is plotted with Potential Energy in KJ on the y axis and Reaction Pathway on the x
Leya [2.2K]

Answer:

NOT A

Explanation:

3 0
4 years ago
10. Predict the mass of nitrogen dioxide produced if 2.30 L of ammonia are allowed to react
Scrat [10]

Answer:

Mass of nitrogen dioxide produced = 4.6 g

Explanation:

Given data:

Volume of ammonia = 2.30 L

Mass of nitrogen dioxide produced = ?

Solution:

Chemical equation:

4NH₃ + 7O₂     →      4NO₂ + 6H₂O

Number of moles of ammonia at STP:

PV = nRT

n = PV/RT

n = 1 atm × 2.30 L / 0.0821 atm.L/K.mol × 273 K

n = 2.30 atm .L / 22.414 atm.L/mol

n = 0.1 mol

Now we will compare the moles of ammonia with nitrogen dioxide from balance chemical equation.

                NH₃            :             NO₂

                 4                :               4

                 0.1             :              0.1

Mass of NO₂:

Mass = number of moles  × molar mass

Mass = 0.1 mol  × 46 g/mol

Mass = 4.6 g

7 0
3 years ago
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