Answer;
=28.09 amu
Explanation;
In this problem, they did not give us the percentages. However, since we know the number of atoms, we can easily calculate the percentages. For example:
(460 X 100)/500 = 92%
If we do this for all three isotopes,
(460 × 25)/500 = 5 %
(460 × 15) /500 = 3%
-We get 92%, 5%, and 3%. (We'll assume these are absolute numbers for determining our significant figures).
Now the problem is just like the previous one. First convert the percentages into decimals. Then multiply those decimals by the masses and add. Here's the solution:
= (0.92) X (27.98 amu) + (0.05) X (28.98 amu) + (0.03) X (29.97 amu)
= 25.74 amu + 1.449 amu + 0.8991 amu
= 28.09 amu
The moles of ammonium nitrate needed to dissolve 0.35 moles
The moles of water that will react is 0.35 moles as due to ratio
so mass of water will be 0.35 x 18=6.3g
MASS OF WATER WILL BE 6.3 g
Answer:
Prophase
Explanation:
During prophase, the chromosomes condense, the nucleolus disappears, and the nuclear envelope breaks down.
Answer:
15.4 mol CO₂
Explanation:
5.12 mol C₃H₈ × (3 mol CO₂ / mol C₃H₈) ≈ 15.4 mol CO₂
Answer: Two chlorine atoms
Explanation:
Chlorine is a nonmetal belonging to group 7 of the periodic table. It has an atomic number of 17 distributed as (2, 8, 7), so it has 7 valence electrons and needs JUST ONE to complete its outermost shell.
Cl + e- ---> Cl-
On the other hand, barium is a metal belonging to group 2 on the periodic table. It has an atomic number of 56 with 2
valence electrons in its outermost shell, and gives off the two electrons to form a stable octet structure.
Ba ----> Ba2+ + 2e-
Thus, barium loses its 2 outermost electrons to form a Ba2+ ion, while TWO chlorine atoms receive them to form 2Cl- resulting in an ionic bond in the compound, BaCl2 (Barium Chloride)
Ba2+ + 2Cl- ---> BaCl2
