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zubka84 [21]
3 years ago
13

If g(x)= 2x-1, and h(x)= square root of x, find (goh)(9)

Mathematics
2 answers:
Mashcka [7]3 years ago
6 0

Answer:

The (goh)(9)=5

Step-by-step explanation:

We need to find out the (goh)(9)

Given:- g(x)=2x-1 and h(x)=\sqrt{x}

First we need to find out the composition of (gof)(x)

Replace x in function g(x) with h(x) as;

(goh)(x)=2(h(x))-1

(goh)(x)=2(\sqrt{x})-1

Now put x=9 , in above to get the (goh)(9)

(goh)(9)=2(\sqrt{9})-1

(goh)(9)=2(3)-1

(goh)(9)=6-1

(goh)(9)=5

Therefore, (goh)(9)=5

loris [4]3 years ago
5 0
(goh) = 2(x^1/2)-1
(goh)(9) = 2(9^1/2)-1
= 2(3)-1
= 6-1
= 5
(goh)(9) = 5
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Answer:

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Step-by-step explanation:

Assuming all angle measures are in degrees, the sum of them is 180:

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  9x +9 = 180 . . . . collect terms

  x + 1 = 20 . . . . . . divide by 9

  x = 19 . . . . . . . . . .subtract 1

The value of x is 19.

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3 years ago
Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,
Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is \dfrac{1}{6} = 0.1667 .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

      Numbers on the dice (X)                       P(X)

                      +1                                                 \frac{1}{6}

                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X)  =  \sum X \times P(X)

   =  (+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}

   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

   =  \frac{1+2+3-4+5-6}{6}

   =  \frac{11-10}{6}= \frac{1}{6}

Hence, the expected value of the points earned on a single roll in this game is  \frac{1}{6} = 0.1667 .

4 0
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vekshin1

Answer:

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Step-by-step explanation:

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From the question, you said the three side lengths are given. In such case, we employ the HERO FORMULA.

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Area = √ s(s-a)(s-b)(s-c)

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But since the question insisted that we use 1/2* base * height. Let's use our know of right angle to dissolve that.

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Let's take it this way.

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6 0
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