Question

If g(x)= 2x-1, and h(x)= square root of x, find (goh)(9)

Answer 1

Answer:

The $(goh)(9)=5$

Step-by-step explanation:

We need to find out the $(goh)(9)$

Given:- $g(x)=2x-1$ and $h(x)=\sqrt{x}$

First we need to find out the composition of (gof)(x)

Replace x in function g(x) with h(x) as;

$(goh)(x)=2(h(x))-1$

$(goh)(x)=2(\sqrt{x})-1$

Now put x=9 , in above to get the $(goh)(9)$

$(goh)(9)=2(\sqrt{9})-1$

$(goh)(9)=2(3)-1$

$(goh)(9)=6-1$

$(goh)(9)=5$

Therefore, $(goh)(9)=5$

Answer 2

(goh) = 2(x^1/2)-1
(goh)(9) = 2(9^1/2)-1
= 2(3)-1
= 6-1
= 5
(goh)(9) = 5