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Pani-rosa [81]
3 years ago
11

A dime is 1.25 mm thick. How many meters high would a stack of dimes worth $50 be?

Mathematics
2 answers:
Lady_Fox [76]3 years ago
6 0
The answer is 0.625 because 1 mm=0.001 meter.
Steps:
10x50=500
500x1.25=625
Convert from mm to meters.
Mkey [24]3 years ago
4 0

Answer:

The stack is 6.25m high.

Step-by-step explanation:

A dime is a 10 cent coin.

100 cents make $1.

5000 cents will make $50.

It is given 1 dime is 1.25 mm thick

Thickness of 5000 dimes =1.25 x5000 = 6250 mm

1000 mm = 1m

6250 mm = 6.25m

The stack is 6.25m high.

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A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The
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Using the Sine rule,

\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

A^0+P^0+B^0=180^0\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}

Using the side rule to find the length of wire BP,

\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

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1 year ago
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