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4 years ago

14

What is the equation of a line that passes through (0,-2) and has a slope of 0

2 answers:

Valentin [98]4 years ago

6 0

If we then plug in the slope<span> and y intercept into the slope-intercept formula of </span><span>y=mb+b</span><span> where </span><span>m=</span><span> the slope the </span><span>b=</span><span> the y intercept, then </span>
<span>y=mx+b</span><span> becomes</span>
<span>y=0x+<span>(−2)</span></span><span> which simplifies to </span><span>y=−<span>2
</span></span>

katrin2010 [14]4 years ago

4 0

A slope of 0....this means that u have a horizontal line...which is represented by y = a number....with that number being the y coordinate of ur point (0,-2).
Therefore, ur equation is : y = -2

learn this, it helps...
HOY -- horizontal line, 0 slope, represented by y = a number
VUX -- vertical line, undefined slope, represented by x = a number

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Quesheip Use the number line below, where RS = 6y +2, ST=5y + 9, and RT= 13y - 1 a What is the value of y? b Find RS, ST, and RT

Simora [160]

Answer:

$y = 6$

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$ST = 39$

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Step-by-step explanation:

Given:

$RS = 6y +2$

$ST=5y + 9$

$RT= 13y - 1$

Solving (a): The value of y

From the given parameters, we understand that

$RT = RS + ST$

Substitute values for RS, ST and RT

$13y - 1 = 6y + 2 + 5y + 9$

Collect Like Terms

$13y - 6y - 5y = 1 + 2 + 9$

$2y = 12$

Divide both sides by 2

$y = \frac{12}{2}$

$y = 6$

Solving (b):

<em>The value of RS</em>

Substitute 6 for y in $RS = 6y +2$

$RS = 6 * 6 + 2$

$RS = 36 + 2$

$RS = 38$

<em>The value of ST</em>

Substitute 6 for y in $ST=5y + 9$

$ST = 5 * 6 + 9$

$ST = 30 + 9$

$ST = 39$

<em>The value of ST</em>

Substitute 6 for y in $RT= 13y - 1$

$RT = 13 * 6 - 1$

$RT = 78 - 1$

$RT = 77$

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