Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
Answer:
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Step-by-step explanation:
Let the kite is the quadrilateral A B C D with the two pairs of adjacent congruent sides. (Please find the attached diagram also)
Now, its given in question, see from figure,
AB is congruent to AD
BC is congruent to DC
So, let us join the points A & C to form AC ; and points B and D to form BD.
So, AC is common side to triangles ABC and ADC.
So, Because AB ≈AD
BC ≈ DC
And, AC is common, therefore,
triangle ABC is congruent to triangle ADC
⇒∠ ABC ≈ ∠ADC
The above are the angle.
Idk I but can u help me Bc I’m in 7th and the person that helped me doesn’t know what they are talking about
Sine law to find angle R
![\displaystyle \frac{\sin R}{122}= \frac{\sin 64}{187.5} \\ \\ \sin R = \frac{122\sin 64}{187.5} \\ \\ R = \sin^{-1} \left[ \frac{122\sin 64}{187.5} \right] \\ \\ R \approx 35.7899447211](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csin%20R%7D%7B122%7D%3D%20%5Cfrac%7B%5Csin%2064%7D%7B187.5%7D%20%5C%5C%20%5C%5C%0A%5Csin%20R%20%3D%20%20%5Cfrac%7B122%5Csin%2064%7D%7B187.5%7D%20%5C%5C%20%5C%5C%0AR%20%3D%20%5Csin%5E%7B-1%7D%20%5Cleft%5B%20%5Cfrac%7B122%5Csin%2064%7D%7B187.5%7D%20%5Cright%5D%20%5C%5C%20%20%5C%5C%0AR%20%5Capprox%2035.7899447211)
All angles in triangle add to 180 so we can find angle P
P = 180 - R - Q
P = 180 - 35.7899447211 - 64
P = 80.2100552789
sine law with angle P to find length of RQ
![\displaystyle \frac{RQ}{\sin P} = \frac{187.5}{\sin 64} \\ \\ RQ = \frac{187.5\sin P}{\sin 64} \\ \\ RQ = \frac{187.5\sin 80.2100552789}{\sin 64} \\ \\ RQ = 205.57](https://tex.z-dn.net/?f=%5Cdisplaystyle%0A%5Cfrac%7BRQ%7D%7B%5Csin%20P%7D%20%3D%20%5Cfrac%7B187.5%7D%7B%5Csin%2064%7D%20%5C%5C%20%5C%5C%0ARQ%20%3D%20%5Cfrac%7B187.5%5Csin%20P%7D%7B%5Csin%2064%7D%20%20%5C%5C%20%5C%5C%0ARQ%20%3D%20%5Cfrac%7B187.5%5Csin%2080.2100552789%7D%7B%5Csin%2064%7D%20%20%5C%5C%20%5C%5C%0ARQ%20%3D%20205.57)
or use cosine law
![RQ = \sqrt{187.5^2 + 122^2 - 2(187.5)(122) \cos80.2100552789} \\ RQ \approx 205.57](https://tex.z-dn.net/?f=RQ%20%3D%20%5Csqrt%7B187.5%5E2%20%2B%20122%5E2%20-%202%28187.5%29%28122%29%20%5Ccos80.2100552789%7D%20%5C%5C%20RQ%20%5Capprox%20205.57)
either way the answer is 205.57 feet