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3 years ago

Why do ionic compounds hve high melting points and boiling points

1 answer:

8 0

Ionic compounds have high melting and boiling points due to their strong ionic bonding. This is due to the strong electrostatic interactions between positive and negative ions. That's why a large amount of energy is needed to break the bonding between ions.

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A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i

musickatia [10]

0.75 atm. is the answer

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3 years ago

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What is the [H] in a solution with a pH of 9.92

professor190 [17]

Answer:

the solution is acidic as its ph has already exceeded the neutral level

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3 years ago

Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li (s) + N2 (g) → 2Li3N (s) In a particular ex

seraphim [82]

Answer: 6.71 g

Explanation: $6Li(s)+N_2(g)\rightarrow 2Li_3N$

${\text{no of moles}}=\frac{\text{Given mass}}{\text{Molar mass}}$

${\text {moles of lithium}}=\frac{4g}{6.914g/mol}=0.578moles$

$\text{moles of nitrogen}=\frac{4g}{28g/mol}=0.143moles$

Limiting reagent is the reagent which limits the formation of product. Excess reagent is one which is in excess and thus remains unreacted.

Thus lithium is the limiting reagent and nitrogen is the excess reagent.

As can be seen from the balanced chemical equation, 6 moles of lithium reacts with 1 mole of nitrogen to give 2 moles of lithium nitride.

Thus 0.578 moles of lithium react with 0.096 moles of nitrogen.

6 moles of lithium give = 2 moles of lithium nitride

Thus 0.578 moles of lithium give= $\frac{2}{6}\times {0.578}=0.19moles$ of lithium nitride.

Mass of lithium nitride $Li_3N={\text {no of moles}}\times {\text {Molecular mass}}$

Mass of lithium nitride $Li_3N$ = ${0.192moles}\times {34.83g/mol}=6.71g$

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3 years ago

What's the valency of lead in pbO2

Andru [333]

The valence of lead is 4.

Hence the name of the compound is called Lead (IV) oxide.

<h3>Further explanation</h3>

Given

PbO₂ compound

Required

The valence of Pb

Solution

The oxidation number of element O in the compound = -2, except for OF₂ the oxidation state = + 2 and the peroxides (Na₂O₂, BaO₂) the oxidation state = -1 and superoxide, for example KO₂ = -1/2.

The oxidation state in the uncharged compound = 0,

So The oxidation state of Pb :

Pb + 2.(-2) = 0

Pb - 4 = 0

Pb = +4

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3 years ago

Which of the following compounds would be named with a name that ends in -yne?

lianna [129]

Anything with a triple bond ends with -yne so that would be C

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3 years ago

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