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Mumz [18]
3 years ago
10

What is 3/4 times 12

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

bruh its      9

Step-by-step explanation:

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If FGH QRS, find the measure of Q<br><br> A. 9<br> B.28<br> C.11<br> D.34
Ne4ueva [31]

Answer:

  • 28°

Step-by-step explanation:

<u>Since ΔFHG ≅ QRC, the corresponding angles are congruent:</u>

  • ∠F = ∠Q
  • (2x + 10)° = (3x + 1)°
  • 3x - 2x = (10 - 1)°
  • x = 9°

<u>Then, the angle Q measures:</u>

  • ∠Q = (3*9 + 1)° = 28°
6 0
2 years ago
This is my question!<br> Please help answer!!!
svp [43]

The x and y coordinates of point S are increased by three to get to the midpoint.

(2,1) ----> (5,4)

To get to point t increase the coordinates by three again.

(5,4) -----> (8,7)

answer: (8,7)

6 0
3 years ago
It is given that quadrilateral ABCD is a kite. We know
NemiM [27]

Answer:

Kite

Perpendicular

Reflexive

HL

Step-by-step explanation: Just did it on edg 2021.

3 0
2 years ago
Read 2 more answers
What is the correct way to write 9 x 9 x 9 in exponential form?
Harlamova29_29 [7]

Hey!

----------------------------------------------

Solution:

Put all the answer choices into expanded form.

3^9 = 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3

1^8 = 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1

9^3 = 9 x 9 x 9

8^1 = 8

----------------------------------------------

Answer:

We can see that the only way to write to write 9 x 9 x 9 in exponential form is c) 9^3

----------------------------------------------

Hope This Helped! Good Luck!

5 0
2 years ago
Read 2 more answers
Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1
kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

<u>Background of the Discriminant</u>

The discriminant b^2-4ac applies to quadratic equations when they are organised in standard form: ax^2+bx+c=0.

All quadratic equations can be solved with the quadratic formula: x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}.

When b^2-4ac is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

<u>Solving the Problem</u>

<u />3x^2+5x=-1<u />

We're given the above equation. It hasn't been organised completely in ax^2+bx+c=0, but we can change that by adding 1 to both sides to make the right side equal to 0:

3x^2+5x+1=0<u />

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0
2 years ago
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