What is 3/4 times 12

Jessica is 4 years younger than Jennifer now. In 10 years, Jessica will be twice the age that Jennifer is now. Find the present

blsea [12.9K]

So we don't know both of their age but we do know that Jessica is 4 year younger so let make x stand for Jennifer age and n is for jessica so our equation needs to be n + 10 = 8 + 2n subtract n from both sides so now we have 10 = 8 + n then subtract 8 from both sides so now we have 10 - 8 = n so jessica is 2 but now we need to find Jennifer age by adding 4 to 2 = 6

jessica is 2 and Jennifer is 6

4 0

2 years ago

PLZ I`M TIMED

madam [21]

Answer:

I'm assuming that the variable h is for height, and the W (the total) is for weight, so the answer would be 60 120/263 or 60.456273764259Step-by-step explanation

7 0

2 years ago

Read 2 more answers

I think I got this for the most part just need to be surs

defon

Answer:

a) 37.33 tons

b) 96 tons

c) Week 2

Step-by-step explanation:

a) 40+40+32=112÷3=37.33 tons

b) 32+40+24=96 tons

c) Week 2

6 0

3 years ago

What is 3/8 as a decimal and percent?

vova2212 [387]

3/8 as a decimal equals=
3÷8=0.375

3/8 as percent equals=
0.375= 37.5%
:)

4 0

2 years ago

Read 2 more answers

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$