A 50 meter path surrounds a rectangular garden . The width of the garden is two-thirds its length. find its area.

1 answer:

7 0

$w-width\\l-length\\\\2w+2l=50\to w+l=25\\w=\frac{2}{3}l\\\\substitute:\\\\\frac{2}{3}l+l=25\\\\\frac{5}{3}l=25\ \ \ \ /\cdot\frac{3}{5}\\\\l=15\ (m)\\\\w=\frac{2}{3}\cdot15=10\ (m)\\\\Area:A_{\fbox{ }}=wl\to A_{\fbox{ }}=10\cdot15=150\ (m^2)$

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What is the height of the following triangle if the area is 60 square meters? Do not round your answer.

olga nikolaevna [1]

Answer: Height = 8 m

Step-by-step explanation: We have to find h...

We're given two values

A = 60

B = 15

60 is equal to 1/2 x 15

Solve for h:

h = 60 / (1/2 x 15)

h = 60 divided by 7.5

h = 8

I hope this helps!

5 0

3 years ago

Help please I don’t understand any of this

sveta [45]

The two angles form a straight line which is equal to 180 degrees. This makes the angles supplemtary.

To find x, add the two angles together to equal 180:

7x + x+20 = 180

Combine like terms:

8x + 20 = 180

Subtract 20 from both sides:

8x = 160

Divide both sides by 8:

X = 20

6 0

3 years ago

Read 2 more answers

What is -3x^2-4x-4=0

ss7ja [257]

Answer:

<h2>no real solution</h2>

Step-by-step explanation:

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