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3 years ago

A 50 meter path surrounds a rectangular garden . The width of the garden is two-thirds its length. find its area.

1 answer:

7 0

$w-width\\l-length\\\\2w+2l=50\to w+l=25\\w=\frac{2}{3}l\\\\substitute:\\\\\frac{2}{3}l+l=25\\\\\frac{5}{3}l=25\ \ \ \ /\cdot\frac{3}{5}\\\\l=15\ (m)\\\\w=\frac{2}{3}\cdot15=10\ (m)\\\\Area:A_{\fbox{ }}=wl\to A_{\fbox{ }}=10\cdot15=150\ (m^2)$

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ANSWER PLZ 99 POINTS AND BRAINLIEST. WHAT IS THE SQUARE ROOT OF 169?

Brums [2.3K]

13 x 13
or

13^2 (13²) will give you 169
and when two negative numbers are put together you get a positive so in this case -13 would work too.

7 0

3 years ago

Read 2 more answers

Order the fractions from least to greatest 1/6, 2/5, 3/5, 3/7. Please show work TY

german

The order will be 1/6 2/5 3/7 3/5

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3 years ago

Cos²x + sin^2x/cscx-cot^2x

Anna [14]

Answer:

Step-by-step explanation:

I am assuming you want to simplify this.

cos^2 x + sin^2 x = 1 and

csc^2 x = 1 + cot^2 x so csc^2x - cot^2 x = 1

So the answer is 1/1 = 1.

5 0

3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

kow [346]

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that $n = 292, \pi = \frac{52}{292} = 0.178$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207$

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

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3 years ago

Ann desires to grow tall sunflower plants. She wonders how the amount of water she provides the sunflowers will affect their gro

bixtya [17]

Answer: a

Step-by-step explanation:

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3 years ago