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Zanzabum
3 years ago
12

A 50 meter path surrounds a rectangular garden . The width of the garden is two-thirds its length. find its area.

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0
w-width\\l-length\\\\2w+2l=50\to w+l=25\\w=\frac{2}{3}l\\\\substitute:\\\\\frac{2}{3}l+l=25\\\\\frac{5}{3}l=25\ \ \ \ /\cdot\frac{3}{5}\\\\l=15\ (m)\\\\w=\frac{2}{3}\cdot15=10\ (m)\\\\Area:A_{\fbox{ }}=wl\to A_{\fbox{ }}=10\cdot15=150\ (m^2)
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A tree is 58 inches tall. how tall is it in feet and inches
mart [117]
A foot is 12 inches.
12 can go into 58 evenly 4 times, since 12• 4 equals 48 but 12 • 5 equals 60. This means that the tree is at least 4 feet. Then to find the leftover inches we do 58-48 equals 10, therefore the answer is 58 inches translates to 4 feet and 10 inches.
8 0
3 years ago
Identify square root of 2 as either rational or irrational and approximate to the tenths place. Rational: square root of 2 ≈ 1.5
gtnhenbr [62]
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3 years ago
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The city of Raleigh has 10400 registered voters. There are two candidates for city council in an upcoming election: Brown and Fe
iVinArrow [24]

Answer:

Step-by-step explanation:

Hello!

a) The population of interest is the registered voters of the city of Raleigh.

b) This population is finite and its size is 10400 voters.

c) The sample was taken by making a telephone poll, calling 400 registered voters.

d) The sample size is n= 400 voters

The number of people that answered they'd vote for Brown are 151, so the sample proportion of voters that would vote for bron is:

p= 151/400= 0.3775 ≅ 0.38

e) To know how many people is expected to vote for Brown based on the results of the telephone poll you can do the following calculation:

10400*0.38= 3952

Based on the information obtained from the sample, it is expected that only 3952 voters will vote for Brown.

4 0
3 years ago
If sec theta = - √30 / 3, find cos theta.<br> if sin(-theta) = -0.97, find cos (π/2 - theta).
Cloud [144]

Step-by-step explanation:

\cos \theta  =  \frac{1}{ \sec\theta }  =  -  \frac{3}{ \sqrt{30} }  =  -  \frac{3 \sqrt{30} }{30}   =  -  \frac{ \sqrt{30} }{10}

\cos( \frac{\pi}{2} -  \theta )=  \cos \frac{\pi}{2}  \cos \theta  +   \sin \frac{\pi}{2}  \sin \theta

Note that

\sin( - \theta) =  -  \sin \theta

\cos \frac{\pi}{2}  = 0 \:  \:  \:  \:  \:  \sin \frac{\pi}{2}  = 1

Therefore,

\cos( \frac{\pi}{2} -  \theta )  = 0.97

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3 years ago
Apply a 90 degree rotation to the point (1, 2)
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Hmm I use to know this wait a second I’ll answer it
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