Answer: A 729
Step-by-step explanation:
We are given vertices of a rectangle (0, −4) , (−1, −3) , (2, 0) , and (3, −1).
Length is the distance between (0, −4) and (−1, −3) points.
Width is distance between (−1, −3) and (2, 0) points.
<u>Computing length:</u>
<u>Computing Width :</u>
<h3>
Area of the rectangle = Length × Width </h3>
= 
.
The zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
<h3>How to determine the zeros of the function?</h3>
The function is given as:
f(x) = x^3 + 3x^2 + 2x
Factor out x in the above function
f(x) = x(x^2 + 3x + 2)
Set the function to 0
x(x^2 + 3x + 2) = 0
Factorize the expression in the bracket
x(x + 1)(x + 2) = 0
Split the expression
x = 0, x + 1 = 0 and x + 2 = 0
Solve for x
x = 0, x = -1 and x = -2
Hence, the zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
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