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Mariana [72]
3 years ago
11

6c = 7c − 7 with work shown

Mathematics
2 answers:
Gala2k [10]3 years ago
7 0

Answer:

c = 7

Step-by-step explanation:

6c = 7c - 7

Subtract 6c to both sides

0 = c - 7

Add 7 to both sides

c = 7

andre [41]3 years ago
6 0

Answer:

c = 7

Step-by-step explanation:

Step 1: Subtract 7c from both sides.

6c − 7c = 7c − 7 − 7c

−c = −7

Step 2: Divide both sides by -1.

-c/-1 = -7/-1

c = 7

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\large\begin{array}{l} \textsf{Substitute}\\\\ \mathsf{2x-1=u\quad\Rightarrow\quad 2\,dx=du}\\\\\\ \textsf{so (i) becomes}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^u\,du}\\\\ =\mathsf{\dfrac{1}{2}\cdot \dfrac{1}{\ell n\,3}\,3^u+C}\\\\ =\mathsf{\dfrac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}


\large\begin{array}{l} \boxed{\begin{array}{c}\mathsf{\displaystyle\int\!3^{2x-1}\,dx=\frac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}}\qquad\checkmark \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154165


\large\textsf{I hope it helps. :-)}
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Tags: <em>integrate indefinite integral substitution exponential base logarithm log ln composite integral calculus

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4 0
3 years ago
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V125BC [204]

Answer:

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Step-by-step explanation:

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3 years ago
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