I’m guessing that this is for systems of equations?
n - nickels
d - dimes
These are the equations you start off with.
n = 5d-2
0.95 = 0.10d+0.05n
Substitute the top equation for n into the variable n in the bottom equation.
0.95 = 0.10d+0.05(5d-2)
Solve for d.
0.95 = 0.10d+0.25d-0.10
1.05 = 0.35d
3 = d
Substitute d into the top equation and solve for n.
n = 5(3)-2
n = 15-3
n = 12
There are 3 dimes and 12 nickels in the coin purse! Hope this helped <3
Answer:
1.22 i think
Step-by-step explanation:
Answer:
-21/22
Step-by-step explanation:
1.Apply fraction cross multiply
2. Simplify
3.Expand
4.Subtract 24 from both sides
5.simplify
6. Subtract 18x form both sides
7.Simpiify, then divide both sides by -22to get answer.
Three-forty one over one thousand XD
2x-3+7x-10=32
9x-13=32
9x=32+13
9x=45
x=5
