All categories

3 years ago

What is 1.44 as a fraction

Mathematics

1 answer:

LenaWriter [7]3 years ago

8 0

11/25 is 1.44 as a fraction simplified

You might be interested in

Please help will mark brainliest

ExtremeBDS [4]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

2x - m x= 4 m= 2 can you help me because I wanna know what the answer

NeTakaya

Answer:

Step-by-step explanation:

2x-m

When you substitue in the values for x and m:

2(4)-2

Now you can solve the equation:

2(4)-2

8-2

So this leads to the answer

2x-m=6 or 2(4)-2=6

6 0

3 years ago

Determine the domain for the graphed function: Please help meeee

Rom4ik [11]

Answer:

Step-by-step explanation:

First, domain refers to the x axis. So you would find the lowest number on the X axis, -2, and then you look at the kind of dot on that number. It is an open dot, which means that it is all the numbers up to -2, but does not include -2. Then you find the highest number, in this case 2. Looking at the dot that is marking it, it is a closed dot, meaning it includes the number 2. So the domain would be numbers between -2 and 2, but does not include -2. all numbers greater than -2, x, all numbers less than and equal to 2.

7 0

3 years ago

The heights of a group of boys and girls at a local middle school are shown on the dot plots below. 2 dot plots with number line

atroni [7]

Answer:sushi love sushi sushi is life and life is sushi

Step-by-step explanation:

8 0

3 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

2 years ago