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vivado [14]
2 years ago
9

73 cubed root lies between which two integers

Mathematics
2 answers:
tankabanditka [31]2 years ago
6 0
Between 8 and 9. Because the square root of  73 is<span> 8.54400374532</span>
Leno4ka [110]2 years ago
3 0
Lies between sqrt 81 and 64
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Solve the equation 3x = 9.5 Show and justify each step you take to solve the equation . 3x = 9 Write the equation 9 Divide each
zimovet [89]

Answer:

3x=9.5, you would divide 3 on each side to get x by itself, so (3x)/3=9.5/3, which would lead to be x=9.5/3 or x= 3 and 1/6th, 3 + 1/6

Step-by-step explanation:

4 0
2 years ago
13. Find the equations of the straight lines which passes
ipn [44]

9514 1404 393

Answer:

  • y = 1/2x +2
  • y = -2x +7

Step-by-step explanation:

The slope of a line is the tangent of the angle it makes with the x-axis. The given line has a slope of -1/3, so the lines we want will have slopes of ...

  m1 = tan(arctan(-1/3) +45°) = 0.5 . . . . . using a calculator

  m2 = tan(arctan(-1/3) -45°) = -2

Of course, these two lines are perpendicular to each other, so their slopes will have a product of -1: (0.5)(-2) = -1.

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We can use the point-slope form of the equation for a line to write the desired equations:

  y = m(x -h) +k . . . . . line with slope m through point (h, k)

<u>Line 1</u>:

  y = 1/2(x -2) +3

  y = 1/2x +2

<u>Line 2</u>:

  y = -2(x -2) +3

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3 0
3 years ago
1, 5, 17, 53, ... Use inductive reasoning to create a general rule for the sequence. A. Multiply by 3, then add 2. B. Multiply b
Basile [38]
The answer to this problem is the letter "A" which is "Multiply by 3, then add 2"
and can be written a N = 3n + 2
At first, we have initial value such n = 1
Then the second value is:
N = 3*1 + 2
N = 5
The third value is:
N = 3*5 + 2
N=17
The next values are:
N = 3*17 + 2
N= 53
The letter "A" is the inductive reasoning to the given sequence.
6 0
3 years ago
-5(4b+ 7) = distributive property
vova2212 [387]

Answer:

-20b-35

Step-by-step explanation:

8 0
2 years ago
2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
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