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melisa1 [442]
4 years ago
13

Sao can text 1500 words per hour. He needs to text a message with 85 words. He only has 5 minutes between classes to complete th

e text. Can he do it in 5 minutes? (show work)
Mathematics
2 answers:
Amiraneli [1.4K]4 years ago
5 0
First divide 1500 by 60 to see how many words he can write in a minute. he can text 25 words a minute. multiply that by five to see how many words he can text in five minutes. he can text 125 words in five minutes, so he can text 85 words in a minute.

The answer is yes.
Tanzania [10]4 years ago
5 0

Answer:

minecraft good

Step-by-step explanation:

fortnite bad

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Trevor is swimming laps to raise money for the local food bank. He earns $1.85 per lap and has already swum 23 laps.
finlep [7]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

The inequality is 1.85x - 42.55 > 100. 42.55 is the amount already raised, 1.85x is number of laps times the money raised by them. 
5 0
3 years ago
A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea
Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

Let <em>C </em>the total cost of the rectangular field.

The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>.  Thus

C=4x+4y+4y+16x\\C=20x+8y

We know that the total area of rectangular field should be 2250 square yards,

x\cdot y=2250

We can say that y=\frac{2250}{x}

Substituting into the total cost of the rectangular field, we get

C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}

We have to figure out where the function is increasing and decreasing. Differentiating,

\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}

Next, we find the critical points of the derivative

20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30

Because the length is always positive the only point we take is x=30. We thus test the intervals (0, 30) and (30, \infty)

C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0

we see that total cost function is decreasing on (0, 30) and increasing on (30, \infty). Therefore, the minimum is attained at x=30, so the minimal cost is

C(30)=20(30)+\frac{18000}{30}\\C(30)=1200

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0
3 years ago
The intersection of two planes can be a point true or false
sergij07 [2.7K]

Answer:

true

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
please help! i'll mark brainliest if correct! Use the second image attached to answer the question! HELP ASAP
Jobisdone [24]
The right answer is c have a nice day
6 0
3 years ago
Help question is in attachment
WARRIOR [948]

Answer:

50

Step-by-step explanation:

90-40 = 50

7 0
3 years ago
Read 2 more answers
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