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JulijaS [17]
2 years ago
11

If sales tax is 8 percent how much would you pay for a book that costs $15.00​

Mathematics
2 answers:
mylen [45]2 years ago
8 0
The cost of the book would be 16.20
Nastasia [14]2 years ago
3 0

Answer:

16.2

Step-by-step explanation:

8% of 15=1.2

15+1.2=16.2

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If Randy sells 8 times as many vacuum cleaners as Janice, and Janice sells 690 vacuum cleaners per year, on average, how many do
drek231 [11]

Randy sells, in average, 460 vacuum cleaners per month.

<h3>How many vacuum cleaners does Randy sell each month?.</h3>

First, we know that Janice sells 690 units per year.

There are 12 months in a year, so the amount that she sells, in average, per month is:

J = 690/12 = 57.5

This means that Janice sells, in average, 57.5 units per month. And Randy sells 8 times as many, then we can solve the product:

R = 8*57.5 = 460

This means that Randy sells 460 units per month.

If you want to learn more about products:

brainly.com/question/10873737

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7 0
2 years ago
These figures are congruent. What is the length of side LM?
sergiy2304 [10]

Answer:

5

Step-by-step explanation:

congruent means sides are equal

4 0
2 years ago
Read 2 more answers
Solve for y: when 3x + 2x+3y =180
Crank
Y = - 5x / 3 + 60

that's your answer!
4 0
3 years ago
In Richmond, Chloe ordered $40 worth of sushi. She knew that when the bill came, she would need to pay Richmond sales tax for 5%
maks197457 [2]

Answer:

$50

Step-by-step explanation:

Given data

Cost of sushi= $40

Tax= 5%

Tip= 20%

Let us find the amount of the tax and the tip

Tax

=5/100*40

=0.05*40

=$2

Tip

=20/100*40

=0.2*40

=$8

Hence the total amount paid is

=40+2+8

=$50

6 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
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