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2 years ago

Find the image of A(-2,4) under a translation (x,y)->(x-2,y-3)

Mathematics

1 answer:

vichka [17]2 years ago

4 0

Answer:

Point A would be at the coordinates, (-4, 1). Hope this helps!

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Solve this system of equations using elimination. X-6=-17 -2x+12y=7

AfilCa [17]

Answer:

Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

Point Form:

(−11,−5/4)

Equation Form:

x=−11,y=−5/4

8 0

2 years ago

What is the solution to the following system? x+y+z=6 x-y+z=8 x+y-z=0

Ghella [55]

I don't really know if this is correct but I think it is x+y+z=14

4 0

3 years ago

Read 2 more answers

25. Michael is studying population changes in two

g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

Average Rate of Change

Bird A:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = $\frac{f(18) - f(0)}{x_{2} - x_{1} }$

Average = $\frac{9.1 - 8.3}{18 - 0}$

Average = 0.045

Bird B: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = $\frac{f(18) - f(0)}{x_{2} - x_{1} }$

Average = $\frac{68.7 - 0}{18 - 0}$

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

4 0

2 years ago

A trucking company uses matrix A , shown below, to represent the driving time in hours for 6 trucking routes. A = [ 4 6 8 ]

zepelin [54]

Each element of the matrix are multiplied by the scalar to form a matrix of

same size as the original matrix in matrix scalar multiplication.

$60 \cdot A = \left[\begin{array}{ccc}240\4&360&480\\360&480&600\end{array}\right]$

Reasons:

The matrix A is presented as follows;

$A = {\left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right]}$

Using the multiplication of a matrix and a scalar, we have;

$60 \cdot A = 60 \cdot \left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right] = \left[\begin{array}{ccc}60 \times 4&60 \times 6&60 \times 8\\60 \times 6&60 \times 8&60 \times 10\end{array}\right] = \left[\begin{array}{ccc}\mathbf{240}&\mathbf{360}&\mathbf{480}\\\mathbf{360}&\mathbf{480}&\mathbf{600}\end{array}\right]$