Answer:
Step-by-step explanation:
“the center of the ellipse is located below the given co-vertex”
Co-vertex and center are vertically aligned, so the ellipse is horizontal.
Equation for horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
with
a² ≥ b²
center (h,k)
vertices (h±a, k)
co-vertices (h, k±b)
foci (h±c,k), c² = a² -b²
One co-vertex is (-8,9), so h = -8.
One focus is (4,4), so k = 4.
Center (h,k) = (-8,4)
c = distance between center and focus = |-8 - 4| = 12
b = |9-k| = 5
a² = c² + b² = 169
(x+8)²/169 + (y-4)²/25 = 1
Answer:
Step-by-step explanation:
we know that
The area of a triangle applying the law of sines is given by the formula
where
A is the included angle between the sides b and c
substitute the given values
9.6 guests which isn't technically possible so it has to be 10 according to my calculations
Slope of line ab = 6-2 / 8-4 = 4/4 = 1
So the slope of the perpendicular line is -1/1 = -1
This line passes through the midpoint of ab
The midpoint of ab = ( 8+4 / 2 , 2+6 / 2) = (6, 4)
Finding the equation of the perpendicular line:-
y - y1 = -1(x - x1) where x1 = 6 and y1 = 4:-
y - 6 = -1(x - 4)
y = -x + 10 is the answer
Answer: Y= -4X -6
Step-by-step explanation:
First, you need to get y by itself
so subtract 4x and 6 from each side
y = -4x -6
