Answer:
Create the table and choose a set of x values. Substitute each x value (left side column) into the equation. Evaluate the equation (middle column) to arrive at the y value. An Optional step, if you want, you can omit the middle column from your table, since the table of values is really just the x and y pairs.
Step-by-step explanation:
Specify a name for the function.
Specify a name and data type for each input parameter.
Specify the routine attributes.
Specify the RETURNS TABLE keyword.
Specify the BEGIN ATOMIC keyword to introduce the function-body.
Specify the function body.
Answer:
The probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% is 0.9946.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
![\mu_{\hat p}=p](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%20p%7D%3Dp)
The standard deviation of this sampling distribution of sample proportion is:
![\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%20p%7D%3D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D)
The information provided here is:
<em>p</em> = 0.27
<em>n</em> = 423
As <em>n </em>= 423 > 30, the sampling distribution of sample proportion can be approximated by the Normal distribution.
The mean and standard deviation of the sampling distribution of sample proportion are:
![\mu_{\hat p}=p=0.27\\\\\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.27\times(1-0.27)}{423}}=0.0216](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%20p%7D%3Dp%3D0.27%5C%5C%5C%5C%5Csigma_%7B%5Chat%20p%7D%3D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%3D%5Csqrt%7B%5Cfrac%7B0.27%5Ctimes%281-0.27%29%7D%7B423%7D%7D%3D0.0216)
Compute the probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% as follows:
![P(|\hat p-p|](https://tex.z-dn.net/?f=P%28%7C%5Chat%20p-p%7C%3C0.06%29%3DP%28p-0.06%3C%5Chat%20p%3Cp%2B0.06%29)
![=P(0.27-0.06](https://tex.z-dn.net/?f=%3DP%280.27-0.06%3C%5Chat%20p%3C0.27%2B0.06%29%5C%5C%5C%5C%3DP%280.21%3C%5Chat%20p%3C0.33%29%5C%5C%5C%5C%3DP%28%5Cfrac%7B0.21-0.27%7D%7B0.0216%7D%3C%5Cfrac%7B%5Chat%20p-%5Cmu_%7B%5Chat%20p%7D%7D%7B%5Csigma_%7B%5Chat%20p%7D%7D%3C%5Cfrac%7B0.33-0.27%7D%7B0.0216%7D%29%5C%5C%5C%5C%3DP%28-2.78%3CZ%3C2.78%29%5C%5C%5C%5C%3DP%28Z%3C2.78%29-P%28Z%3C-2.78%29%5C%5C%5C%5C%3D0.99728-0.00272%5C%5C%5C%5C%3D0.99456%5C%5C%5C%5C%5Capprox%200.9946)
*Use a <em>z</em>-table.
Thus, the probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% is 0.9946.
Answer:
Step-by-step explanation:
whats the question
Answer:
x = 9.5
Step-by-step explanation:
Answer:
The linear equation used to find the cost to rent the shoes is ![24.75+x=32](https://tex.z-dn.net/?f=24.75%2Bx%3D32)
Cost to rent the shoes is $7.25.
Step-by-step explanation:
Given:
Cost of per game of bowling = $4.95
Number of games played = 5
Total money paid = $32
We need to find the cost to rent the shoes.
Solution:
Let the cost to rent the shoes be 'x'.
So we can say that;
Total money paid is equal to sum of Cost of per game of bowling multiplied by Number of games played and cost to rent the shoes.
framing in equation form we get;
![5\times4.95+x=32\\\\24.75+x=32](https://tex.z-dn.net/?f=5%5Ctimes4.95%2Bx%3D32%5C%5C%5C%5C24.75%2Bx%3D32)
Hence The linear equation used to find the cost to rent the shoes is ![24.75+x=32](https://tex.z-dn.net/?f=24.75%2Bx%3D32)
On solving the above equation we will find the value of 'x'.
Now we will subtract both side by 24.75 we get;
![24.75+x=32-24.75\\\\x= \$7.25](https://tex.z-dn.net/?f=24.75%2Bx%3D32-24.75%5C%5C%5C%5Cx%3D%20%5C%247.25)
Hence Cost to rent the shoes is $7.25.