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VikaD [51]
4 years ago
12

Find the area of segment CED given the following information:

Mathematics
2 answers:
Hitman42 [59]4 years ago
6 0
Area of sector CAD = 72 / 360 x pi x 6^2 = 7.2pi = 22.6195 in^2

Therefore, area of segment CED = 22.6195 - 17.18 = 5.44 in^2
ICE Princess25 [194]4 years ago
6 0

Answer: 5.43 square inches

Step-by-step explanation:

Here, the area of triangle ACD = 17.18 square inches,

And, the radius of the triangle having center A = 6 inches

The central angle of the arc CED = 72°

Hence, the area of the sector CAD = \frac{72}{360}\pi (6)^2

= \frac{2592\pi}{360}

= \frac{8138.88}{360}

= 22.608  square inches

Since, the area of CED = The area of sector CAD - Area of triangle ACD

= 22.608 - 17.18

= 5.428 ≈ 5.43 square inches.

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4. Solve the following equations and verify your answers: (i) 3 (x + 7) = 18​
stiv31 [10]

Answer:

8.33333333333

Step-by-step explanation:

Solution for 3x-7=18 equation:

3x - 7 = 18

3x = 18 + 7

3x = 25 (divide both sides by 3 to get x)

3x/3 = 25/3

x = 8.33333333333

3 0
3 years ago
The question about triangles is below.
rusak2 [61]

Answer:

A.

Step-by-step explanation:

5 0
3 years ago
-8x+3=8x+27 I need help plz I’m trash at math
belka [17]

Answer:

-1.5

Step-by-step explanation:

<u>See steps below:</u>

  • -8x+3=8x+27
  • -8x + 3 - 8x - 3 = 8x+ 27 - 8x - 3          ⇒ add -8x - 3 to both sides in order to collect like terms in the different sides of equation
  • -16x = 24                                               ⇒ simplified
  • x= 24/-16                                               ⇒ divide
  • x= - 1.5                                                   ⇒ answer
3 0
3 years ago
Which of the followeing represents the solution...<br><br> 4(9+3z)≤12+6z
julia-pushkina [17]

Solving the inequality 4(9+3z)\leq 12+6z we get z\leq -4

Step-by-step explanation:

We need to solve the inequality 4(9+3z)\leq 12+6z

Solving:

4(9+3z)\leq 12+6z

Multiplying 4 with terms inside the bracket.

36+12z\leq 12+6z

Adding -36 on both sides:

12z\leq 12+6z-36

Adding -6z on both sides

12z-6z\leq 12-36

6z\leq -24

Divide both sides by 6

z\leq -4

So, solving the inequality 4(9+3z)\leq 12+6z we get z\leq -4

Keywords: Solving inequalities

Learn more about Solving inequalities at:

  • brainly.com/question/1465430
  • brainly.com/question/6703816
  • brainly.com/question/11788572
  • brainly.com/question/4192226

#learnwithBrainly

8 0
4 years ago
Two different squares have an areas of 36m° and 49m°
sleet_krkn [62]

The difference of the length of two different squares having area of 36 square meters and 49 square meters is 1 m.

According to the question,

We have the following information:

Two different squares have an area of 36 square meters and 49 square meters.

We know that the following formula is used to find the area of square:

Area = side*side

Side*side = 36

Side = √36

Side = 6 m

Now, side of the another square:

Side*side = 49

Side = √49

Side = 7 m

Now, the difference in the length of the sides of these two squares:

7-6

1 m

Hence, the difference of the length of two different squares having area of 36 square meters and 49 square meters is 1 m.

To know more about difference of the length here

brainly.com/question/20750630

#SPJ1

4 0
1 year ago
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