Find the area of segment CED given the following information:
2 answers:
Answer: 5.43 square inches
Step-by-step explanation:
Here, the area of triangle ACD = 17.18 square inches,
And, the radius of the triangle having center A = 6 inches
The central angle of the arc CED = 72°
Hence, the area of the sector CAD =
=
=
= square inches
Since, the area of CED = The area of sector CAD - Area of triangle ACD
= 22.608 - 17.18
= 5.428 ≈ 5.43 square inches.
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Remark
I take it that you want to know the ratio of the radii. If this is not correct, leave a comment below my answer.
You could do this by giving the spheres a definite volume, like 1 and 8 and then solve for r for one of them and then use the other sphere to find it's radius. It is not exactly the best way, and if you are going to to a physics class you want to be doing this using cancellation.
Step One
Set up the Ratio for the volumes.
Step Two
Setup the equation for V1/V2 using the definition for a sphere. V = 4/3 pi r^3
Step Three
Cancel the 4/3 and pi on the top and bottom of the fractions on the right.
You are left with 1/8 = (r1)^3/ (r2)^3
Step Four
Take the cube root of both sides.
cube root 1/8 = 1/2
Cube root of (r1)^3 = r1
Cube root of (r2)^3 = r2
Step Five
Answer
Answer <<<<<<<
I take it that you want to know the ratio of the radii. If this is not correct, leave a comment below my answer.
You could do this by giving the spheres a definite volume, like 1 and 8 and then solve for r for one of them and then use the other sphere to find it's radius. It is not exactly the best way, and if you are going to to a physics class you want to be doing this using cancellation.
Step One
Set up the Ratio for the volumes.
Step Two
Setup the equation for V1/V2 using the definition for a sphere. V = 4/3 pi r^3
Step Three
Cancel the 4/3 and pi on the top and bottom of the fractions on the right.
You are left with 1/8 = (r1)^3/ (r2)^3
Step Four
Take the cube root of both sides.
cube root 1/8 = 1/2
Cube root of (r1)^3 = r1
Cube root of (r2)^3 = r2
Step Five
Answer