There are 10 chips altogether. 4 of them are white.
4/10 is the chance of lifting out a white chip
There are 3 of them left and 9 chips altogehter.
4/10 * 3/9
12/90
4/30
2/15
Comment
(my edit) it is not that 2/15 is wrong (although it is not entirely right).
1/3 is the correct answer if you assume that what happened during the first draw has nothing to do with what will happen on the second. It is like saying if you throw 11 heads in a row with a fair coin, what are the chances of throwing a heads on the 12th throw? The answer is 1/2. That is the same kind of question you have asked.
The two of us who have responded have really responded to what are the chances of drawing 2 white chips. The question really does not restrict us in a way that prevents us from saying that. I'll stick with
B <<<< answer
but I think it would be nice if the writer of the question made it clear that 1/3 should be the proper answer. I am glad you came back and posted the right answer. It makes me think.
The semi right answer is B <<<<----
If my reasoning bothers anybody, I'll reedit again. I'm only leaving it because sometimes a mistake is more instructive than a given answer.
Answer:
starts wuth 46, and sells half, so she has 23. then when she buys 17 more she then has 40.
if you are asked to show work its 46/2=23, then 23+17=40!
Here it is given that the width is x ft and total length of the fence is 2400 ft .
Let the length be y ft
So we have
Let A represents area, and area is the product of length and width .
So we get
Substituting the value of y, we will get
Second part
The area is maximum at the vertex, and vertex is
And
And that's the required dimensions .
Answer:
The answer: 1/10x (k-7)
Step-by-step explanation:
-Move 2 units left:y=(1/x +2)
-Move 3 units up:y= (1/x +2)+3
So the equation is y= (1/x +2)+3
