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3 years ago

10

A direct variation always goes through the origin of the coordinate plane. TrueFalse

1 answer:

german3 years ago

6 0

Answer:

true

Step-by-step explanation:

thats true

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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

My mother is 12 years more than twice my age.after 8 years she will be 20 years less than three times my age...find my age and m

Mnenie [13.5K]

You are correct for the first part, you would be 16 and your Mom would be 44. After 8 years, you would be 24 and your mother would be 52. You solve the second part by adding 8 to 16 which equals 24. Then multiply 24 times 3 which equals 72. Lastly, subtract 20 from 72 to find your mother's new age. Which would be 52.

Hope this helps !

4 0

3 years ago

WILL GIVE BRAINLIEST

valina [46]

1000. You need to divide 1500 by 30 to get 50. Then you multiply that by 20. Please mark as brainliest!

7 0

4 years ago

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Each square below represents one whole,<br> What percent is represented by the shaded area?<br> %

liberstina [14]

Answer:

...........................

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3 years ago

The integers have to =0

Marrrta [24]

Answer:

123 - 94 - 7

Step-by-step explanation:

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3 years ago