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Otrada [13]
3 years ago
11

The circumference of a circular pond is 654 feet.Whats the diameter at a rate of 6 feet per second?

Mathematics
1 answer:
Alex73 [517]3 years ago
8 0
<span>To find the answer we need to find the raduis

Circumference = 2πr
r=</span>\frac{Circumference}{2 \pi }
r=\frac{654}{2 \pi }
 = 104.08

The diameter is 2r, hence the diameter is 208.16

If the rate to cross is 6ft. per second, time can be found by dividing the raduis by 6

It would take 34.7 seconds
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Please help and give explanation
Firlakuza [10]

Answer:

100 mins

Step-by-step explanation:

total no of gallons pool can hold=4500

gallons pool already holds=1500

rate of adding water= 30 gallons per min

time he can continue filing= 4500-1500/30

=3000/30

=100 minutes (m value)

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8 0
3 years ago
"solve each system by graphing"
garik1379 [7]
Put them into y=mx+b
y=1/3x -1 
y=2/3x-4
Graph them. Where they touch is your answer. No touch? No solution. Same line? Infinite solutions.
Second set: Same thing.
Solution to first set is (9,2)
3 0
3 years ago
When x = 12, y = 8. Find x when у = 12
Bad White [126]

Answer:

y =  \frac{12 \times 12}{8}  = 18

7 0
3 years ago
Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
What is the equation of the line that is perpendicular to 3x -6y =2 and contains the point (-2,--5)​
julsineya [31]

Answer:

y=-2x-12

Step-by-step explanation:

first, putt 3x-6y=2 in standard form:

subtract 3x from both sides: -6y=-3x+2

divide both sides by -6 to isolate y: y=1/2x-1/3

if the other line is perpendicular to this, you must find the slope by finding the opposite reciprocal of 1/2x: -2

now we have 2 points a slope, so we use the point-slope formula: y-y1=m(x-x1)

y+2=-2(x+5)

Use the distributive property: y+2=-2x-10

subtract 2 for both sides to isolate y: y=-2x-12

5 0
3 years ago
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