i = 3c
i = c + 14
set both equations equal to each-other, we can
solve for c, we must.
3c = c + 14
subtract c from both sides, we must.
2c = 14
divide both sides by 2, we must.
c = 7
7 years old, Christopher is.
Answer:
∠V = 32°
Step-by-step explanation:
VW = UV
⇒ Isosceles triangle. So, the angles opposite sides are equal.
∠W = ∠U
∴ ∠W = ∠U = 74°
<h3>Angle sum property</h3>
Sum of all angles of triangle = 180
74 + 74 + ∠V = 180
148 + ∠V = 180
∠V = 180 - 148
∠V = 32°
Answer:
x = -3
Step-by-step explanation:
Okay, the first thing to do is get that 8 away from the fraction. How can we do it? When you have 2³ you have 8, is the same thing, so let's do it:
2³⁰/(2³)⁹ = 2^x
When you have a number with the shape (a^x)^y, you can write it as a^(x•y), so:
(2³)⁹ = 2^3•9 = 2²⁷
Now we have:
2³⁰/2²⁷ = 2^x
When you have a division like this: (a^x)/(a^y), you can write it as a^(x-y), so:
2^(30-27) = 2^x
2^-3 = 2^x
Now you know that x = -3
Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
_______________
The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18
