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alex41 [277]
3 years ago
5

For what values of x is the expression below defined?

Mathematics
2 answers:
Llana [10]3 years ago
8 0

Answer:

A) -5\leq x < 1

Step-by-step explanation:

First, let's notice that we need positives numbers inside both roots. The root of a negative number is a math error (we are not dealing with complex numbers right now). With that information, let's analyze the options:

A) -5\leq x < 1

If we add 5 in this inequation, we have

-5+ 5\leq x+5 < 1+5

0\leq x+5 < 6

That's means the number in the first root is positive, great!

Now, we want 1-x to be positive:

-5\leq x < 1

5\geq -x > -1 (remember that the inequation changes side when we multiply by a negative number, (-1) in this case)

1+5\geq 1-x > 1-1

6\geq 1-x > 0

It's positive!

This is the correct answer but let's see why the others are incorrect.

B)5> x \leq-1

We just need to find a number that fits the inequation but causes at least one root to have a negative number inside.

For example, -6.  

5>-6

-6 \leq -1

But -6+5 = -1 is negative

C) 5 > x > 1

In this case, the number 2 fits the inequation but it causes the second root to have a negative number inside, 1 - 2 = -1

D) 5 \leq x \leq 1

This option can't be correct because there is no number smaller than 1 and bigger than 5.

sveticcg [70]3 years ago
5 0
The answer is most likely B
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A parabola can be drawn given a focus of (2, 4)(2,4) and a directrix of x=4x=4. Write the equation of the parabola in any form.
kipiarov [429]

Answer:

The equation of the parabola is;

x = -(1/4)·(y - 4)² + 3

Step-by-step explanation:

The given focus of the parabola is f = (2, 4)

The directrix of the parabola is x = 4

The vertex form of the equation of the parabola can be expressed as follows;

x = a·(y - k)² + h

(y - k)² = 4·p·(x - h)

Where;

(h, k) = The vertex of the parabola

(h + p, k) = The focus of the parabola

x = h - p = The directrix

Therefore, k = 4

h + p = 2...(1)

h - p = 4...(2)

∴ 2·h = 6

h = 6/2 = 3

From equation (1), we have;

p = 2 - 3 = -1

p = -1

From the equation of the parabola in the form, (y - k)² = 4·p·(x - h), we have;

The equation of the parabola is (y - 4)² = 4 × (-1) ·(x - 3)

Therefore, we have;

(y - 4)² = -4·x + 12

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The equation of the parabola is x = -(1/4)·(y - 4)² + 3

y² -8·y + 16 = -4·x + 12

4·x = 8·y - y² - 16 + 12 = 8·y - y² - 4

x = 2·y - y²/4 - 1 = -y²/4 + 2·y - 1

The equation of the parabola can also be written in the form

x = -y²/4 + 2·y - 1 = -0.25·y² + 2·y - 1

6 0
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