There are

ways of selecting two of the six blocks at random. The probability that one of them contains an error is

So

has probability mass function

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then
Answer:
3x-y=-2
Step-by-step explanation:
9x-5x-x-3y+2y=-2
3x-y=-2
The answer would be log base 2 of 6 over log base 2 of 3
8-5=3 is the remaining half
weekly allowance=2(1÷2) where (1÷2) is 3
2×3=6
The weekly allowance should be 6.
Answer:
3
√
2
Explanation:
First put change the words into an equation:
√
3
×
√
6
Now you can multiply them together as you would normally multiply:
√
3
×
√
6
=
√
18
Now let's prime factor 18 and see if there are any squares that we can take out of it to simplify. All we have to see is if there are 2 numbers that are the same:
18
/ \
6
3
/ \
2
3
As you can see, we have a square:
3
×
3
=
9
So take
√
9
out of
√
18
. You should have:
√
9
√
2
But since
√
9
=
3
we can simplify further to make:
√
9
√
2
→
3
√
2
Step-by-step explanation: