Evaluate 10 sigma n=4 5n + 2
1 answer:
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Answer:
4 · 1/4 (I-0) = (A-0)∧2
see details in the graph
Step-by-step explanation:
Matrix A is expressed in the form A∧2=I
To proof that Matrix A is both orthogonal and involutory, if and only if A is symmetric is shown by re-expressing that
A∧2=I in the standard form
4 · 1/4 (I-0) = (A-0)∧2
Re-expressing
A∧2 = I as a graphical element plotted on the graph
X∧2=I
The orthogonality is shown in the graphical plot displayed in the picture. Orthogonality expresses the mutually independent form of two vectors expressed in their perpendicularity.
Answer:
Solution of the system of equations will be (6, 6).
Step-by-step explanation:
Table for the first equation,
x 0 2 4 6 8
y 3 4 5 6 7
(x, y) (0, 3) (2, 4) (4, 5) (6, 6) (8, 7)
We have got the values of y by substituting the values of x in the given equation for the table.
Similarly, for the other equation,
y = 2x - 6
x 0 2 4 6 8
y -6 -2 2 6 10
(x, y) (0, -6) (2, -2) (4, 2) (6, 6) (8, 10)
By analyzing both the tables we find (6, 6) is a common point in both the tables.
That represents the points of intersection of both the lines.
Therefore, solution of the system of equations will be (6, 6)