Question

Imagine a dihybrid cross. If there are 1000 progeny (we are talking about beetles here), approximately how many beetles would you expect to be homozygous recessive for both traits?

Answer 1

Answer:

We would expect 63 snails to be homozygous recessive for both traits.

Explanation:

Dihybrid cross

This is a cross between two distinct groups with different observed traits. Independent segregation is observed on the allelic pair for the genes in the separate chromosomes.

The first filial generation produces 4 similar offspring, the second filial generation, would demonstrates a phenotypic ratio of 9:3:3:1.

On dividing the 1,000 progeny on the aspect of phenotypic ratio 9:3:3:1, we can infer an approximate number of 63 (62.5) snails to be homozygous recessive for both traits.

We will calculate on the aspect of the phenotypic ratios and proportions,

Therefore

9+3+3+1 = 16.

1,000*1/16 = 62.5

62.5 can be approximated to 63