Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Factorize using the difference of squares identity.

Then

Well first add up all the numbers of marbles (which is 34 in total) and divide it by the number of black marbles.
(which should give you 8/34)
Then simplify the fraction and you should get 4/17
Given:
assessment rate = 51%
tax rate = 53.26 per 1,000
53.26 / 1000 = 0.05326
0.05326 x 100% = 5.326%
Effective tax rate = assessment rate * tax rate
ETR = 51% * 5.326%
ETR = 2.72%