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Oksi-84 [34.3K]
2 years ago
9

Let f(x)=4x^2-2 f(t+1)

Mathematics
1 answer:
dusya [7]2 years ago
4 0

Answer:

f(x) = 4 {x}^{2}  - 2 \\ f(t + 1) = 4 {(t + 1)}^{2}  - 2 \\  = 4( t + 1)(t + 1) - 2 \\  = 4( {t}^{2}  + 2t + 1) - 2 \\  = 4 {t}^{2}  + 8t + 4 - 2 \\  = 4 {t}^{2}  + 8t + 2

I hope I helped you^_^

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