Question

A jogger jogs from one end to the other of a straight track in 1.13 min and then back to the starting point in 1.63 min. What is the jogger’s average speed in jogging to the far end of the track (assuming the track is 100 m long)

Answer 1

His average speed is 1.38 min

Answer 2

Answer:

Average speed of jogger,s=72.46 m/min

Explanation:

Total distance covered by a body divided by the elapsed time to cover that distance is known as average speed of that body.

We have given length of track=100m

Therefore total distance covered by the jogger,

$d=100m+100m\\d=200m$

Total time taken by joggers to cover 200m distace,

$t=1.13 min+1.63m$

t=2.76 min

Therefore average speed of jogger,

$s=\frac{d}{t}$...............(1)

put values of d and t in equation 1

we got,

$s=\frac{200 m}{2.76 min}$

average speed of jogger,s=72.46 m/min